Yes; a triangle is formed:
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m∡A = 17° ;
m∡B = 137° (given) ;
m∡C = 26° ;
a = 6 ;
b = 14 (given) ;
c = 9 (given) .
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Explanation:
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Note:
The law of sines:
(sin A) / a = (sin B) / b = (sin C) / c ;
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Given:
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B = 137 ;
c = 9 ;
b =14 ;
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(sin B) / b = (sin C) / c ;
(sin 137) / 14 = (sin C) / 9 ;
(0.681998360062) / 14 = 0.0487141685758571 = (sin C) / 9 ;
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sin C = (0.0487141685758571) * (9) ;
sin C = 0.4384275171827139 ;
Take the "arc sin" of each side of the equation; to isolate "C" on one side of the equation; and to solve for "C" ;
arc sin (C) = arc sin ( 0.4384275171827139) ;
C = 26.003593520741 ; round to 26.
If all angles of a triangle add up to 180 degrees: then:
A + B + C = 180 ;
A + 137 + 26 = 180 ;
A + 163 = 180 ;
Subtract "163" from each side of the equation; to isolate "A" on one side of the equation; and to solve for "A" ;
A + 163 − 163 = 180 − 163 ;
A = 17 ;
Now, to solve for "a" ;
(sin A) / a = (sin B)/ b ;
(sin 17) / a = 0.0487141685758571 ;
(0.0487141685758571) a = (sin 17) ;
Divide EACH SIDE of the equation by: "(0.0487141685758571)" ;
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to isolate "a" on one side of the equation; and to solve for "a" ;
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[(0.0487141685758571)a ] / (0.0487141685758571) =
(sin 17) / (0.0487141685758571) ;
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a = (sin 17) / (0.0487141685758571) ;
= (0.292371704723) / (0.0487141685758571) ;
a = 6.0017796314787227112 ; round to "6" .
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Answer:
1340 is the amount kimber needs
