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Romashka [77]
3 years ago
6

(4.3 * 10-3)(2 x 10-2)​

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
3 0

<em>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</em>

<em>➷ </em>(4.3\cdot10-3)(2\cdot 10-2)<em />

<em>➷ </em>= (43 - 3)((2) (10) -2)<em />

<em>➷ </em>= 40 ((2) (10)-2)<em />

<em> ➷ </em>= 40(20 - 2)<em />

<em> ➷ </em>= (40)(18)<em />

<em> ➷ </em>= 720<em />

<em>✽</em>

<em>➶ Hope This Helps You!</em>

<em>➶ Good Luck (:</em>

<em>➶ Have A Great Day ^-^</em>

<em>↬ May ♡</em>

<em />

slavikrds [6]3 years ago
3 0

Given expression:

    (4.3 x 10^{-3}) (2 x 10^{-2})

Solving this equation,

   (4.3 x 10^{-3}) (2 x 10^{-2})  = 4.3 x 10^{-3} x 2 x 10^{-2}

                                      =  (4.3 x 2)  x 10⁻³ x 10⁻²

                                       = 8.6 x 10⁻³ ⁺⁽⁻²⁾

                                       = 8.6 x 10⁻⁵

The solution of this problem is 8.6 x 10⁻⁵

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Calculus Problem
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and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

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where ∆x is the thickness of the section. Then the volume would be

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where we take advantage of symmetry in the first line.

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\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

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+4        +4

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