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Andrew [12]
3 years ago
10

Segment AB has endpoints A(–4, 6) and B(1, 4). After a dilation, centered at the origin, the image of A is (–6, 9). Without meas

uring the distance, explain how you could find the image of B
Mathematics
2 answers:
Ksivusya [100]3 years ago
4 0
With A and its image one can get the dilation factor;
That is dilation scale factor = -6/-4 or 9/6 = 3/2
Therefore, to get the image of B we multiply the coordinates of B by the dilation factor; 
(1,4) 3/2 = (1.5, 6)
Thus the image of B = (1.5,6)
-BARSIC- [3]3 years ago
4 0

Answer:

To find the image of B, first find the scale factor for the dilation. The scale factor should be greater than 1 because the image of A is farther from the origin than A. Divide the coordinates of the image of A by the coordinates of A: –6/–4 = 3/2 and 9/6 = 3/2, so the scale factor is 3/2. Now, apply the dilation to B by multiplying the coordinates by 3/2 to get ((3/2)(1), (3/2)(4)), or (3/2, 6).

Step-by-step explanation:

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The admission fee at an amusement park is $2.00 for children and $6.80 for adults. On a certain day, 388 people entered the park
spin [16.1K]

Answer: 188 children and 200 adults were admitted.

Step-by-step explanation:

Let x represent the number of children that were admitted that day.

Let y represent the number of adults that were admitted that day.

On a certain day, 388 people entered the park. It means that

x + y = 388

The admission fee at the amusement park is $2.00 for children and $6.80 for adults. The admission fees collected that day totaled $1736. It means that

2x + 6.8y = 1736- - - - - - - - - - - 1

Substituting x = 388 - y into equation 1, it becomes

2(388 - y) + 6.8y = 1736

776 - 2y + 6.8y = 1736

- 2y + 6.8y = 1736 - 776

4.8y = 960

y = 960/4.8

y = 200

x = 388 - y = 388 - 200

x = 188

4 0
3 years ago
What is the percent of change of $65 to $75
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The number of swimmers at a city pool on Monday was twice the number who were there on Tuesday. The number at the pool on Wednes
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Answer:

102 1/3 swimmers

Step-by-step explanation:

Let

Number of swimmers on Tuesday = x

Number of swimmers on Monday = 2x

Number of swimmers on Wednesday = 3x - 11

Total swimmers for all 3 days = 625

x + 2x + (3x - 11) = 625

3x + 3x - 11 = 625

6x = 625 - 11

6x = 614

x = 614 / 6

= 102 2/6

x = 102 1/3 swimmers

Number of swimmers on Tuesday = x = 102 1/3 swimmers

Number of swimmers on Monday = 2x

= 2(102 1/3)

= 204 2/3

Number of swimmers on Wednesday = 3x - 11

=3(102 1/3) - 11

= 307 - 11

= 296

6 0
3 years ago
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