Seems to be an arythmetic sequence
common difference is 3 (increases by 3 each time)
an=a1+d(n-1)
d=3
a1=8
an=8+3(n-1)
an=8+3n-3
an=3n+5
Answer: 188 children and 200 adults were admitted.
Step-by-step explanation:
Let x represent the number of children that were admitted that day.
Let y represent the number of adults that were admitted that day.
On a certain day, 388 people entered the park. It means that
x + y = 388
The admission fee at the amusement park is $2.00 for children and $6.80 for adults. The admission fees collected that day totaled $1736. It means that
2x + 6.8y = 1736- - - - - - - - - - - 1
Substituting x = 388 - y into equation 1, it becomes
2(388 - y) + 6.8y = 1736
776 - 2y + 6.8y = 1736
- 2y + 6.8y = 1736 - 776
4.8y = 960
y = 960/4.8
y = 200
x = 388 - y = 388 - 200
x = 188
Answer:
102 1/3 swimmers
Step-by-step explanation:
Let
Number of swimmers on Tuesday = x
Number of swimmers on Monday = 2x
Number of swimmers on Wednesday = 3x - 11
Total swimmers for all 3 days = 625
x + 2x + (3x - 11) = 625
3x + 3x - 11 = 625
6x = 625 - 11
6x = 614
x = 614 / 6
= 102 2/6
x = 102 1/3 swimmers
Number of swimmers on Tuesday = x = 102 1/3 swimmers
Number of swimmers on Monday = 2x
= 2(102 1/3)
= 204 2/3
Number of swimmers on Wednesday = 3x - 11
=3(102 1/3) - 11
= 307 - 11
= 296