10³ · x = 630
x = ?
10³ = 10 × 10 × 10 = 1,000
630 ÷ 1000 = x
630 ÷ 1000 = 0.63
x = 0.63
So we have:
10³ · 0.63 = 630
The answer is down below following the order 6~9
6. A
7. C
8.C
9. D
Answer:
2 x 20^2
Step-by-step explanation:
I did it on paper and looked it up to make sure
A set with n elements has 2^n subsets, including the empty set and the complete set.
Your set has 2^6 = 64 subsets.
3 significant figures
0 is only significant if it is enclosed by significant figure.
here 0 is enclosed by significant figures 1 and 5 and is therefore significant.
105 has 3 significant figures
