The slope is -4.500
Hope this helped :)
Step-by-step explanation:
what answer is needed ? the result of the calculation ?
I assume this is the case.
remember that regarding the sequence of operations brackets are first, then exponents, then "dot" operations (× and ÷), and only at the very least come the "dash" operations (+ and -).
and that a combination of - + or + - results in -.
14 + 16 ÷ 2³ - (12 + 3²) ÷ 7 + 2 × (-5) =
14 + 16 ÷ 2³ - (12 + 9) ÷ 7 - 2 × 5 =
14 + 16 ÷ 2³ - 21 ÷ 7 - 2 × 5 =
14 + 16 ÷ 8 - 21 ÷ 7 - 2 × 5 =
14 + 2 - 3 - 10 = 3
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
c = F-32; 68-32 = 36°C.
Step-by-step explanation:
the real conversation equation is f = 9/5 C + 32. but for the sake of this problem we are ignoring the coefficient.
so it's 36°C
