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Gnesinka [82]
2 years ago
8

Please help me with this question Ty

Mathematics
1 answer:
Lunna [17]2 years ago
6 0

Answer:

124.6

Step-by-step explanation:

27/x = 13/60, 13x = 1620, x = 124.6

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One number is 8 more than another. If the sum of the smaller number and twice the larger number is 46, find the two numbers.Let
valkas [14]

Answer:

x = 18 y = 10

Step-by-step explanation:

let the first number be x

let the second number be y

x = y + 8..... equation 1

2x + y = 46.... equation 2

x is the larger number

y is the smaller number.

Rearrange the equation and add equation 1 to equation 2.

x - y = 8

+ 2x + y = 46

-------------------

3x + 0 = 54

3x = 54

divide both sides by 3

x = 54/3

x = 18

Substitute x = 18 into equation 1

x = y + 8

18 = y + 8

collect like terms

y = 18-8

y = 10

3 0
3 years ago
A rental car company charges $35 a day plus $.15/mi for a mid-size car. A customer owes $117.25 for a three-day rental. How many
Molodets [167]
The base charge is 35 dollars per day. He rented the car for 3 days, so before you add in the mileage you have to multiply 35 x 3 days for 105 dollars. Then you have to take the remaining charge and divide it by the charge per mile to get the number of miles driven.  Lets set up the equation.

d= number of days rented
m= number of miles driven

35(d) + .15(m) = 117.25
35(3) + .15m = 117.25
105 + .15m = 117.25
.15m = 117.25 - 105
.15m = 12.25
m = 12.25/.15
m = 81.67

So he drove 81.67 miles
8 0
3 years ago
The average mass of an ant is approximately 3 × 10 − 3 grams. The average mass of a giraffe is approximately 2 × 10 3 kilograms.
Vika [28.1K]

Given that average mass of an ant = 3 \times 10^{-3}grams.

Given that average mass of a giraffe = 2 \times 10^{3} Kilograms.

Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.

Like convert kilogram into gram or gram into kilogram.

I'm going to convert kilogram into gram using formula

1 Kg = 1000 g


So the average mass of a giraffe = 2 \times 10^{3} *10^3 grams.


Now we just need to divide mass of giraffe by mass of ant to find the answer.

\frac{2 \times 10^{3} *10^3 }{3 \times 10^{-3} }

= \frac{2 \times 10^{3} *10^3 *10^{3}}{3  }

= \frac{2 \times 10^{3+3+3}}{3  }

= \frac{2 \times 10^9}{3  }

= \frac{2}{3  } \times 10^9

=666666666.667

Hence final answer is \frac{2}{3  } \times 10^9 which is approx 666666666.667.

3 0
3 years ago
If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time ca
aleksandr82 [10.1K]

Answer:

(a)8.0mg

(b)36.87 hours

(c)-0.168

Step-by-step explanation:

The amount of Valium in that person's bloodstream at any time can be modeled with the exponential decay function A ( t ) = 10 e^{ -0.0188 t (t in hours)

(a)After 12 Hours

A ( 12) = 10 e^{ -0.0188*12}\\=7.98\\\approx 8.0 mg $(to the nearest tenth of a milligram)

(b)If A(t)=5mg

Then:

5= 10 e^{ -0.0188 t}\\$Divide both sides by 10\\0.5=e^{ -0.0188 t}\\$Take the natural logarithm of both sides\\ln (0.5)=-0.0188 t\\t=ln (0.5) \div (-0.0188)\\$t=36.87 hours (to two decimal places.)

(c)

A ( t ) = 10 e^{ -0.0188 t}\\A'(t)=10(-0.0188)e^{ -0.0188 t}\\A'(t)=-0.188e^{ -0.0188 t}\\$At 6 hours, the rate at which the amount of Valium is decaying therefore is:\\A'(6)=-0.188e^{ -0.0188*6}\\$=-0.168 ( to three decimal places)

3 0
3 years ago
Solve: 512^x-2/(1/64)^3x=512
Agata [3.3K]

Answer:......................................................

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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