Answer:
36.666 (The six keeps going)
Step-by-step explanation:
In this question you'll be trying to find out what x is.
(x-8), this is from the amount of years ago and 2(56-x) is from subtracting 8 with 64 and the 2 came from the fact that Jeremy is twice the age.
(x-8)=2(56-x)
x-8=102-2x
Now we want to have x by itself so we'll add 2x on both sides to remove the -2x from the right side.
3x-8=102 (Add up on both sides)
3x=110 (Divide by 3)
x=36.666
Hello :
<span>3y = x + 6 ...(1)
y – x = 3...(2)
by (2) : y = x+3...(*)
subsct in (1) :
3(x+3) = x+6
3x-x= -9+6
2x= -3
x=-3/2
subsct in (*) : y =-3/2 +3 =3/2</span>
Answer:
We start with the equation:
A: 3*(x + 2) = 18
And we want to construct equation B:
B: X + 2 = 18
where I suppose that X is different than x.
Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:
3*(x + 2) = X + 2
Now we can isolate the variable x.
(x + 2) = (X + 2)/3
x = (X + 2)/3 - 2
Then we need to replace x by (X + 2)/3 - 2 in equation A, and we will get equation B.
Let's do it:
A: 3*(x + 2) = 18
Now we can replace x by = (X + 2)/3 - 2
3*( (X + 2)/3 - 2 + 2) = 18
3*( (X + 2)/3 ) = 18
3*(X + 2)/3 = 18
(X + 2) = 18
Which is equation B.
Answer:
Y(n) = 7n + 23
Step-by-step explanation:
Given:
f(0) = 30
f(n+1) = f(n) + 7
For n=0 : f(1) = f(0) + 7
For n=1 : f(2) = f(1) + 7
For n=2 : f(3) = f(2) + 7 and so on.
Hence the sequence is an arithmetic progression with common difference 7 and first term 30.
We have to find a general equation representing the terms of the sequence.
General term of an arithmetic progression is:
T(n) = a + (n-1)d
Here a = 30 and d = 7
Y(n) = 30 + 7(n-1) = 7n + 23
1. Solve for x in 2x + 5 = 12
2x + 5 = 12 Subtract 5 from both sides.
2x = 7 Divide 2 from both sides.
x = 3.5
2. Substitute 3.5 in for x in 6x + 20
6(3.5) + 20
21 + 20
41
Your answer is 41.
