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Novay_Z [31]
4 years ago
15

What is the answer to # 4???

Mathematics
1 answer:
ivann1987 [24]4 years ago
8 0
5 and 3/4 is the first one
4 ft 3 in the second one

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PLEASE HELP!! A game involves rolling a fair six-sided die. If the number obtained on the die is a multiple of three, the player
Oksana_A [137]

Answer: C

Step-by-step explanation: 1/3 probability

3 0
3 years ago
When X equals eight, Y equals 20 find Y when x equals 42
gavmur [86]
Y is equal to 105 because you divide 42 by 8 and get 5.25 (the amount it increased). then you multiply by its previous version 20 to get 105.
4 0
3 years ago
Read 2 more answers
Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is
Simora [160]
The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: A=s^2
Were 
A is the area in square kilometers 
s is one of the sides of the square
We know for our problem that  the side lengths of the field are 0.9 kilometers, so s=0.9. Lets replace that value in our formula to find A:
A=(0.9)^2
A=0.81 

Now, to find the population density of the filed, we are going to use the population density formula: P_{d}= \frac{I}{A}
where
P_{d} is the population density in <span>in burrows per square kilometer
</span>I is the number of burrows 
A is the are of the field
We know that I=1980 and A=0.81, so lets replace those values in our formula:
P_{d}= \frac{1980}{0.81}
P_{d}=2444.4

We can conclude that the <span>density of prairie dog burrows is approximately 2444 burrws per square kilometer.</span>
5 0
3 years ago
What is the side length of side BC of the triangle?
klio [65]

the Answer would be the  Length of BC = 24 units. Since AB = AC you will get that the  two are equal. Use this t solve for x.

5 0
3 years ago
What are the integer solutions of the inequality |x| &lt; 2 ?
mamaluj [8]
B is the answer. It's any number that is less than 2 and -1 will become 1 because it's the absolute value.
7 0
3 years ago
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