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Serga [27]
3 years ago
8

Archaeologists can determine the diets of ancient civilizations by measuring the ratio of carbon-13 to carbon-12 in bones found

at burial sites. Large amounts of carbon-13 suggest a diet rich in grasses such as maize, while small amounts suggest a diet based on herbaceous plants. The article a Climate and Diet in Fremont Prehistory: Economic Variability and Abandonment of Maize Agriculture in the Great Salt Lake Basina (J. Coltrain and S. Leavitt, American Antiquity, 2002:453-485) reports ratios, as a difference from a standard in units of parts per thousand, for bones from individuals in several age groups. The data are presented in the following table.
Age Group (years) Ratio
0–11 17.2 18.4 17.9 16.6 19.0 18.3 13.6 13.5 18.5 19.1 19.1 13.4
12–24 14.8 17.6 18.3 17.2 10.0 11.3 10.2 17.0 18.9 19.2
25–45 18.4 13.0 14.8 18.4 12.8 17.6 18.8 17.9 18.5 17.5 18.3 15.2 10.8 19.8 17.3 19.2 15.4 13.2
46+ 15.5 18.2 12.7 15.1 18.2 18.0 14.4 10.2 16.7
(a) Construct a complete ANOVA table.
(b) Can you conclude that the concentration ratios differ among the age groups?
(c) Does this data set meet the conditions of the global F test? You need to prove why or why not using plots and other analysis.
(d) UseFisher’sLSDtoconstructconfidenceintervalsforallpair-wisecomparison’softhegroups.
(e) Use Bonferroni’s method to construct confidence intervals for all pair-wise comparison’s of the groups. You may use RStudio to get the appropriate critical value.
(f) Use the Tukey-Kramer method to construct confidence intervals for all pair-wise comparison’s of the groups.
Mathematics
1 answer:
harkovskaia [24]3 years ago
4 0

Answer:

yessirrr

Step-by-step explanation:

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Diseases tend to spread according to the exponential growth model. In the early days of AIDS, the growth factor (i.e. common rat
weqwewe [10]

Answer:

1,887,436,800

Step-by-step explanation:

f(t) = a·b^t

f (t) = number of cases at year t

a = starting value = 1800 in 1983

b = growth factor = 2

t = years since 1983 = 2003 - 1983 = 20

f(t) = 1800·(2)^20 =

1,887,436,800

wyzant

philip p

5 0
2 years ago
Write 0.27 as a fraction
aniked [119]
The answer is: 27/100
4 0
3 years ago
Read 2 more answers
Rachel ate 1 4/6 brownies, and brandy ate 6/7 of a brownie. how many brownies did they eat altogether?​
In-s [12.5K]

Answer:

53/21 OR 2 11/21

Step-by-step explanation:

1 4/6 + 6/7

Change 1 4/6 into an improper fraction

1 4/6 6x1= 6+4= 10/6

Simplify 10/6 --> 5/3

5/3+ 6/7

find a common denominator (21)

35/21+18/21= 53/21

mixed number form is 2 11/21

6 0
3 years ago
Read 2 more answers
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
Can anyone plz help me
Andrew [12]
Let's solve number 7 <span>step-by-step.
</span><span><span>y/23</span>=7
</span>Step 1: Multiply both sides by 23.
<span><span>y/23</span>=7
</span><span><span><span>(<span>y23</span>)</span>*<span>(23)</span></span>=<span><span>(7)</span>*<span>(23)
</span></span></span><span>y=<span>161 is our answer.


</span></span>Let's solve number 8 step-by-step.
<span>n−4.85=12.6
</span>Step 1: Add 4.85 to both sides.
<span>n−4.85+4.85=12.6+4.85
</span>n=17.45 is our answer.
<span>

</span>Let's solve number 12 step-by-step.
<span><span>m/5</span>=8
</span>Step 1: Multiply both sides by 5.
<span><span>m/5</span>=8
</span><span><span><span>(<span>m/5</span>)</span>*<span>(5)</span></span>=<span><span>(8)</span>*<span>(5)
</span></span></span><span>m=40 is our answer.
</span><span>

</span>Let's solve number 16 step-by-step.
<span><span>a/12</span>=8
</span>Step 1: Multiply both sides by 12.
<span><span>a/12</span>=8
</span><span><span><span>(<span>a/12</span>)</span>*<span>(12)</span></span>=<span><span>(8)</span>*<span>(12)
</span></span></span><span>a=<span>96 is or answer.</span></span>
6 0
3 years ago
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