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3 years ago

Help plz its math and i will give brainlest if u answer

Mathematics

2 answers:

lesantik [10]3 years ago

3 0

Answer:

not a right triangle

Step-by-step explanation:

We can use the Pythagorean theorem to see if it is a right triangle

a^2 + b^2 = c^2

15^2 + 12^2 = 21^2

225 + 144 = 441

369 = 441

This is not true so it is not a right triangle

mars1129 [50]3 years ago

3 0

Answer:

Step-by-step explanation:

A triangle is a right angled triangle if sum of squares of two sides is equal to the square of third side.

12²+15²=144+225=369

21²=441

so a²+b²≠c²

it is not a right angled triangle.

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What is the solution for <br> x+y>2<br> 2x-y>1

blagie [28]

Answer:

x>1 and y>1

Step-by-step explanation:

x+y>2....... (i)

2x-y>1...... (ii)

Adding equations (i) and (ii),

x+y+2x-y>2+1

3x>3

x>3/3

x>1.

Putting the value of x in equation (i),

1+y>2

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3 years ago

Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

Dimas [21]

Answer:

From given relation the value of β is 37.5°

Step-by-step explanation:

Given as :

α and β are two acute angles of right triangle

Acute angle have measure less than 90°

Now given as :

$sin(\frac{x}{2} + 2x)$ = $cos(2x +\frac{3x}{2})$

Or, $cos(90° - (\frac{x}{2}+2x))$ = $cos(2x +\frac{3x}{2})$

SO, $(90° - (\frac{x}{2}+2x))$ = $2x+\frac{3x}{2}$

Or, 90° = $2x+\frac{3x}{2}$ + $\frac{x}{2}+2x$

or, 90° = $\frac{4x}{2}$ + 4x

Or, 90° = $\frac{12x}{2}$

So, x = $\frac{90}{6}$ = 15°

∴ $sin(\frac{x}{2} + 2x)$ = $sin(\frac{15}{2} + 30)$

So, $sin(\frac{x}{2} + 2x)$ = sin $\frac{75}{2}$

∴ The value of Ф_1 = $\frac{75}{2}$ = 37.5°

Similarly $cos(2x +\frac{3x}{2})$ = $cos(30 +\frac{45}{2})$

So ,The value of Ф_2 = $\frac{105}{2}$ = 52.5°

∵ β α

So, As 37.5°52.5°

∴ β = 37.5°

Hence From given relation the value of β is 37.5° Answer

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3 years ago

Sole for a.

Kipish [7]

Answer:

There are no solutions.

D) no solution

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2 years ago

BRAINLIEST WILL BE AWARDED!

tatuchka [14]

Answer:

photomath

Step-by-step explanation:

i dont know the answer but photomath is so much easier to get help.

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3 years ago

Read 2 more answers

A sequence starts from -2. The term to term rule is 'square and subtract 3' find the first six numbers of the sequence

alexandr1967 [171]

Answer:

The first six numbers are $-2,1,-2,1,-2,1$

Step-by-step explanation:

First term is $-2$

The term to term rule is 'square and subtract $3$ '

Second term $=(-2)^{2} -3=1$

Third term $=(1)^{2} -3=-2$

Fourth term $=(-2)^{2} -3=1$

Fifth term $=(1)^{2} -3=-2$

Sixth term $=(-2)^{2} -3=1$

The first six numbers are $-2,1,-2,1,-2,1$

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2 years ago