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3 years ago

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You are having a conference call with the CEO of a paper company. You have interpreted the number of trees cut down versus profi

t as the function P(x)=-x^4+x^3+7x^2-x-6. Describe to the CEO what the graph looks like. Use complete sentences & focus on the end behaviors of the graph and where the company will break even (where P(x) = 0).

1 answer:

RideAnS [48]3 years ago

3 0

The graph has domain x ∈ ( 0 , +∞ )
It is first increasing and then decreasing. It has a local minimum and a global maximum.
- x^4 + x³ + 7 x² - x - 6 = ( x - 1 ) ( x + 1 ) ( x + 2 ) ( 3 - x )
The company will break even when P ( x ) = 0
The zeroes are: x 1 = 1, x 2 = 3
The company has a profit when: x ∈ ( 1, 3 )

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12 - t|3r - 2|

r = -6; t = 3

subtitute:

12 - 3 · |3 · (-6) - 2| = 12 - 3 · |-18 - 2| = 12 - 3 · |-20| = 12 - 3 · 20 = 12 - 60 = -48

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3 years ago

Strands Copper wire from a manufacturer are analyzed forstrenghth and conductivity. The Results from 100 strands are asfollows:S

Thepotemich [5.8K]

Answer and explanation:

Given : Strands Copper wire from a manufacturer are analyzed forstrenghth and conductivity. The Results from 100 strands are as follows :

Strength Strength

High Low

High conductivity 74 8

Low conductivity 15 3

To find :

a) If a stand is randomly selected, the probability that is conductivity is high and its strength is high

The favorable outcome is 74

The probability is given by,

$P=\frac{74}{100}=0.74$

b) If a stand is randomly selected, the probability that its conductivity is low or strength is low

Conductivity is low A= 15+3=18

Strength is low B= 8+3=11

Conductivity is low and strength is low $A\cap B=3$

Probability is given by,

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$P(A\cup B)=\frac{18}{100}+\frac{11}{100}-\frac{3}{100}$

$P(A\cup B)=0.18+0.11-0.03$

$P(A\cup B)=0.26$

c) Consider the event that a strand low conductivity and the event that the strand has a low strength. Are these tow events mutually exclusive?

Since the events the stand has low conductivity and the stand has low strength are not mutually exclusive, since there exists some cases in which both the events coincide. i.e. Intersection of both the events exists with probability 0.03.

8 0

3 years ago

Help me please, thank you! :)

EastWind [94]

Answer:

It's 16 units. Just look at the lengths and how many times they are on a shape. The shape is a rectangle, which means there will be two of each length, so just add them all together. 6+6+2+2=16

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3 years ago

The graph of the even function F(X) Has 5 x-intercepts if (6,0) is the one of the intercepts what set of points can be the other

alex41 [277]

f(x) being even means

f(x) = f(-x)

So the zeros come in positive and negative pairs. If there are an odd number of intercepts like there are here, it's because one of them is x=0 which is its own negation.

Given zero x=6 we know x=-6 is also a zero.

So we know three zeros, and know the other two zeros are a positive and negative pair.

The only choice with (-6,0) and (0,0) is A.

Choice A

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3 years ago

Read 2 more answers

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

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3 years ago