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babymother [125]
2 years ago
8

A jogging track is 1/4 mile. Sara ran 14 laps.

Mathematics
2 answers:
dangina [55]2 years ago
5 0

Answer:

6 more laps

Step-by-step explanation:

iogann1982 [59]2 years ago
5 0

Answer:

Sarah need to run 1\frac{1}{2} more miles.

Step-by-step explanation:

In order to tell how much more she needs to run we need to find out how much she ran so far. Since we know that one lap is \frac{1}{4} of a mile, and that she ran 14 laps we can easily find out how much she ran so far by multiplying \frac{1}{4} by 14. And so we get......

(\frac{1}{4} )(14) = \frac{14}{4} = 3\frac{2}{4} = 3\frac{1}{2}

Now that we know how much she ran so far (3\frac{1}{2} miles), in order to find out how much more she has to run we just have to substract the distance she ran so far from the total distance she wants to reach (in our case 5 miles) . After doing this we get the answer which is......

5 - 3\frac{1}{2} = \frac{5}{1} - \frac{7}{2} = \frac{10}{2} - \frac{7}{2} = \frac{3}{2}  = 1\frac{1}{2}

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The graph below describes the journey of a train between two cities
UkoKoshka [18]

Answer:

Step-by-step explanation:

To find : Acceleration in first 15 min . Distance between two cities  Average speed of journey

Solution:

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                    Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

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= 200  km/h²

Distance between two cities

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

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Distance between two cities = 125 km

Average Speed of journey = 125/2  = 62.5  km/hr

Acceleration in first 15 min = 200  km/h²

Distance between two cities = 125 km

Average Speed of journey =  62.5  km/hr

Hope this helps..

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