If two similar triangles have sides in the ratio a : b, then their areas are in the ratio a² : b².
We have the ratio:

Area of the smaler triangle = x
Area of the larger triangle = 567 cm²
Therefore we have the equation:

<h3>Answer: C. 63 cm²</h3>
I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
An exterior angle of a triangle is equal to the sum of the two opposite interior angles. Example : Find the values of x and y in the following triangle. y + 92° = 180° (interior angle + adjacent exterior angle = 180°.)
Answer:
y = -24
Step-by-step explanation:
Direct variation is
y = kx where k is a constant
12 = k*(-1)
12/(-1) =k
-12 = k
The equation is y = -12x
Let x = 2
y = -12(2)
y = -24