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3 years ago

What is the sum of the arithmetic series below?

1 answer:

5 0

Our question transforms to finding the following sum : 3 + 7 + 11 + 15.... upto 15 terms

Use formula for sum of an AP series 

S = (n * (2a + (n - 1)d)) / 2 

n -> no of terms in AP series , so n = 15 
a -> first term in series, so a = 3 
d -> common difference, so d = 4 

Put all values for a, n, d and you will get the sum.

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Find the product. (x2+3x+7)(x^7)= Please help :)

Nesterboy [21]

Answer: x^9+3x^8+7x^7

Step-by-step explanation:

the ^ mean the exponent

4 0

2 years ago

Kylie can afford a $1310-per-month house loan payment. If she is being

Lesechka [4]

Answer:

The amount which she borrow as house loan is $ 48514.56

Step-by-step explanation:

Given as :

The house loan per month afford by Kylie = $1310

The period of loan = 25 Years

The annual rate compounded monthly = 8.4%

Principal = $ P

∵ The per month loan afford amount = $1310

So, The amount afford in 25 years = $1310 × 25 × 12

Or, The amount afford in 25 years = $393,000

Now, from compounded method :

Amount = Principal × $(1+\frac{Rate}{12\times 100})^{12\times Time}$

Or, $393,000 = $ P × $(1+\frac{8.4}{12\times 100})^{12\times 25}$

Or, $393,000 = $ P × $(1.007)^{300}$

Or, $393,000 = $ P × $\frac{393,000}{8.10066}$

∴ P = $ 48514.56

Hence The amount which she borrow as house loan is $ 48514.56 Answer

8 0

3 years ago

A trapezoid has an area of 50 square units. The lengths of the bases are 10 units and 15 units. find the height.

Lera25 [3.4K]

Step-by-step explanation:

area = ( base 1 + base 2 ) ÷ 2 x height

50 = ( 10 + 15) ÷2 x height

50 ÷ 12.5 = height

height = 4

5 0

3 years ago

Please answer this as soon as possible.

Vlad [161]

I’m pretty sure it’s b

7 0

3 years ago

It takes 22 hours for a hosepipe with a flow of 12 litres per minute to fill a swimming pool. How long will it take if its flow

Monica [59]

Answer:

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

Step-by-step explanation:

The volume of the swimming pool can be written as;

Volume V = flow rate × time

V = R×t

V = R1×t1 = R2×t2

R1×t1 = R2×t2

t2 = R1×t1/R2 ........1

Given;

Flow rate R1 = 12 litres per minute

Flow rate R2 = 5 litres per minute

time t1 = 22 hours

Substituting the given values into equation 1;

t2 = R1×t1/R2 = 12×22/5

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

3 0

3 years ago