Answer:
1/18
Step-by-step explanation:
We are considering that we have 2 dices with 6 faces each (so, the probability to gettig any face in any dish is 1/6). To get an 11, we only have two ways to obtain it:
Dice 1= 6 and Dice 2 =5
or
Dice 1= 5 and Dice 2 =6
So, the probability of the event is given as:
P(Dice1=5 ∧ Dice2=6) ∪ P(Dice1=6 ∧ Dice2=5) = P(Dice1=5) x P(Dice2=6) + P(Dice1=6) x P(Dice2=5) = 1/6 x 1/6 + 1/6 x 1/6 = 1/36 + 1/36 = 2/36 = 1/18.
As 1/18 = 0,055, and 0,055 > 0,05, we consider the event as not significative (according to the definition of significance in the sentence).
Answer:
you need to substitute values on the next form of resolving this problem as follows...
A hose fills up a hot tub at a rate of 3.2 gallons per minute. How many hours will it take to fill a 300 gallon hot tub?
please explain the method of unit conversions as thoroughly as possible.
Solution:
The rate of fill up is, Rate = 3.2 Gallons / minute = 3.2 g/min
The hut tub volume is 300 Gallons
You can set up this problem as follows:
Every 3.2 gallons require 1 minute, How many minutes 300 gallons require?
3.2 g 1min
300 g ? min = (300 gallons x 1min/ 3.2 gallons)=(300/32)min
= 93.75 min
or simply the number minutes is the time required (T) the rate is (R) and the volume is (V)
such that T=V/R= (300g/3.2 g/min)= 93.75 min
Answer:
Yes it would
Step-by-step explanation:
Lanie's room is in the shape of a parallelogram.
Lanie has a rectangular rug that is 6 feet wide and 10 feet long.
Area of a rectangle = Length × Width
Area of the rectangular rug = 10 feet × 6 feet
= 60 square feet
We are told that:
The floor of her room is shown below and has an area of 108 square feet.
Hence, the rug would fit on the floor of her room because it's area is within the area of the floor of her room.
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).
Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is = 
g/L
Outgoing rate = 
Integrating both sides
[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram
Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get
Therefore the concentration of salt in the incoming brine is 1.73 g/L
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