y = mx + b slope(m) = 2/3 (-4,8)...x = -4 and y = 8 sub and find b 8 = 2/3(-4) + b 8 = -8/3 + b 8 + 8/3 = b 24/3 + 8/3 = b 32/3 = b equation is : y = 2/3x + 32/3 or 3y = 2x + 32 when y = 10 3(10) = 2x + 32 30 - 32 = 2x -2 = 2x -2/2 = x -1 = x <=== ================= (9,0)(3,y)...slope = 1/2
y = mx + b slope(m) = 1/2 (9,0)...x = 9 and y = 0 sub and find b 0 = 1/2(9) + b 0 = 9/2 + b -9/2 = b equation is : y = 1/2x - 9/2 or 2y = x - 9 sub in 3 for x and solve for y 2y = 3 - 9 2y = -6 y = -6/2 y = -3 <== ================= (8,7)(11,7)...notice how the y values are the same. This means it is a horizontal line. A horizontal line has a slope of 0. ==================== sorry...not too good with the picture graphs
We need to write system of equations for this problem. Reading text we write 1 equation by 1. first lets name our variables x - Kiana cards y - Gary cards z - Monty cards m - Willa cards
x = y-3 which we can write as y = x+3 z = x + 7 m = 2z x + y + z + m = 74
I think easiest way to solve this is to express all variables in last equation and solve for x. x + x+3 + x + 7+ 2x + 14= 74 5x = 50 x = 10 now we just calculate cards given to each friend
Since AB and CD are parallel, ∠D is congruent to ∠A and ∠C is congruent to ∠B. Therefore the two triangles are similar by the AA postulate. Now, the corresponding sides are in proportion