If their perimeters are equal, we can add up all the side lengths of each triangle, and set the perimeters equal to each other to find the value of x that satisfies the equation:
x - 2 + x + 3x + 1 = 2x - 5 + x + 4 + 6x - 7
Combine like terms:
5x - 1 = 9x - 8
And finally, solve for x:
7 = 4x
x =
Therefore, x is equal to .
<em>Hope this helps! :)</em>
Answer:
Proved CA=CB
Step-by-step explanation:
Given,
In ΔABC, CP is perpendicular to AB.
And CP bisects AB.
So, AP=PB and ∠CPA=∠CPB=90°
The figure of the triangle is in the attachment.
Now, In ΔACP and ΔBCP.
AP = PB(given)
∠CPA = ∠CPB = 90°(perpendicular)
CP = CP(common)
So, By Side-Angle-Side congruence property;
ΔACP ≅ ΔBCP
According to the property of congruence;
"If two triangles are congruent to each other then their corresponding sides are also equal."
Therefore, CA = CB (corresponding side of congruent triangle)
CA = CB Hence Proved
