x is the independent variable.
y is the dependent variable.
-3 is the rate of change (slope).
-7 is the initial value.
Step-by-step explanation:
The form of the linear relation is y = m x + b, where
- m is the rate of change (slope)
- b is the initial value(value of y at x = 0)
- x is the independent variable
- y is the dependent variable
∵ The equation of the line is y = -3 x - 7
- Compare it with the form above
∴ m = -3
∵ m is the rate of change
∴ The rate of change is -3
∴ b = -7
∵ b is the initial value
∴ The initial value is -7
∵ y depends on x
∴ x is the independent variable
∴ y is the dependent variable
x is the independent variable.
y is the dependent variable.
-3 is the rate of change (slope)
-7 is the initial value.
Learn more:
You can learn more about the linear equations in brainly.com/question/4152194
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We have the given I = 10^-1 and I₀ = 10^-12.
Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db
The answer is D.
(I used a scientific calculator in solving for L).
The third one down is the correct answer. (-55 and 1)
Answer:
Painting USA is cheaper. They cost $700 dollars. The other place costs $1,000 dollars
Answer:
31.82% probability that this day would be a winter day
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening
In this question:
Event A: Rain
Event B: Winter day
Probability of rain:
0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).
So
Intersection:
Rain on a winter day, which is 0.42 of 0.25. So
If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?
31.82% probability that this day would be a winter day
