Ask question

Ask question

All categories

2 years ago

10

Gotta question what us 9 times 8 Do not answer the question without showing your work or I'm reporting you because your stealing

my points

2 answers:

Aleksandr-060686 [28]2 years ago

8 0

Answer:

72

Step-by-step explanation:

9x8 is the same as 9+9+9+9+9+9+9+9

when you add them together, you get 72.

Wittaler [7]2 years ago

8 0

Answer:

72

Step-by-step explanation:

9x8=72 because it is similar to 9+9+9+9+9+9+9+9 which is equals to 72 and it is also similar to 8+8+8+8+8+8+8+8+8 which is also equals to 72 because multiplication is repeated addition

You might be interested in

Ramiya is using the quadratic formula to solve a quadratic equation. Her equation is x = after substituting the values of a, b,

Stels [109]

Answer:

this is the answer

0 = x2 + 3x + 2

Step-by-step explanation:

3 0

3 years ago

What are the x-intercepts of the graph of the quadratic function

Svetllana [295]

Zero Product Property: if a × b = 0, then either a or b = 0 or both a and b = 0.

(Make sure to set f(x) to zero)

So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x: $0=5x^2+5x-x-1$

Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: $0=5x(x+1)-1(x+1)$

Now you can rewrite the equation as: $0=(5x-1)(x+1)$

Now apply zero product property to the factors to solve for x:

$5x-1=0\\5x=1\\x=\frac{1}{5}\\\\x+1=0\\x=-1$

<u>The x-intercepts are (1/5 ,0) and (-1,0).</u>

5 0

3 years ago

Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or

NARA [144]

Answer:

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

Step-by-step explanation:

The function is:

$f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y$

The partial derivatives of the function are included below:

$\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y$

$\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)$

$\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x$

$\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)$

Local minima, local maxima and saddle points are determined by equalizing both partial derivatives to zero.

$y \cdot (8\cdot y -16\cdot x + 9) = 0$

$x \cdot (16\cdot y - 8\cdot x + 9) = 0$

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

$\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.$

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

$x\cdot (-8\cdot x + 9) = 0$

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

$y\cdot (8\cdot y+9) = 0$

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

$H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}$

The second derivatives of the function are:

$\frac{\partial^{2} f}{\partial x^{2}} = 0$

$\frac{\partial^{2} f}{\partial y^{2}} = 0$

$\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9$

Then, the expression is simplified to this and each point is tested:

$H = -16\cdot y +16\cdot x -9$

S1: (0,0)

$H = -9$ (Saddle Point)

S2: (3/8,-3/8)

$H = 3$ (Local maximum or minimum)

S3: (9/8, 0)

$H = 9$ (Local maximum or minimum)

S4: (0, - 9/8)

$H = 9$ (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

$f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64}$ (Local minimum)

S3: (9/8, 0)

$f(\frac{9}{8},0) = 0$ (Local maximum)

S4: (0, - 9/8)

$f(0,-\frac{9}{8} ) = 0$ (Local maximum)

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

4 0

3 years ago

What is the variance?

kotegsom [21]

Answer:

Variance is the squared deviation and deviation is the difference of observed value from other values

Step-by-step explanation:

Variance is the squared deviation and deviation is the difference of observed value from other values

$variance=\text({standard deviation})^2$

$Variance=\sum\frac{(x-\mu)^2}{N}$

Where, $\mu=\text{mean},N=\text{Number of sample space}$

8 0

3 years ago

A steel pipe 50 cm long has an outside diameter of 2 cm and an inside diameter of 1.8 cm. If the density of the steel is 7.8 gra

never [62]

Answer:

the volume is 50x1.8x2

v=180cm³

therefore, density is mass/volume

Step-by-step explanation:

mass =density x volume

mass= 7.8 x 180cm³

mass= 1,404grams

4 0

3 years ago