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4 years ago

What is the answer of (-5g+9-2g^2)+(3g^2-g)

Mathematics

1 answer:

denis-greek [22]4 years ago

6 0

Answer:g^2-6g+9

Step-by-step explanation:

add the like terms

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The tenth odd number (1 is the first odd number, 3 is the second odd number and so on what are the indicated value or values?? N

Elza [17]

The answer going to be 5

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4 years ago

Explain what the following statement means: Polynomials are closed under the operations of addition and subtraction. Provide one

kirza4 [7]

1. Polynomials are closed under the operations of addition and substraction mean that:

If we add two polynomials, the result is still a polynomial (so still in the set of polynomials)

Also, If we subtract 2 polynomials, the result is a polynomial.

2. Example: given the polynomials :

$M(x)= 3x^{2}+5x-1$ and $N(x)=-6 x^{4}+9 x^{3}+ x^{2} -2x-1$

Addition example:

$M(x)+N(x)=(3x^{2}+5x-1)+(-6 x^{4}+9 x^{3}+ x^{2} -2x-1)=$

$-6 x^{4}+9 x^{3}+x^{2} +3x^{2}-2x+5x-1-1=-6 x^{4}+9 x^{3}+4x^{2}x-2$

Subtraction example:

$N(x)-M(x)=(-6 x^{4}+9 x^{3}+ x^{2} -2x-1)-(3x^{2}+5x-1)$

= $-6 x^{4}+9 x^{3}+ x^{2} -2x-1-3x^{2}-5x+1=$
= $-6 x^{4}+9 x^{3}+ x^{2} -3x^{2}-2x-5x-1+1=-6 x^{4}+9 x^{3}-2x^{2}-x$

So both M(x)+N(x) and N(x)-M(x) are polynomials

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4 years ago

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In the midpoint rule for triple integrals we use a triple riemann sum to approximate a triple integral over a box b, where f(x,

Lana71 [14]

The sub-boxes will have dimensions $\frac{2-0}{2} \times \frac{2-0}{2} \times \frac{2-0}{2} =1\times1\times1=1 \ cubic \ units$

x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $x= \frac{1}{2}$ and $x= \frac{3}{4}$
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $y= \frac{1}{2}$ and $y= \frac{3}{4}$
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $z= \frac{1}{2}$ and $z= \frac{3}{4}$ 

Let $f(x,y,z)=\cos{(xyz)}$

$\int\limits \int\limits \int\limits {f(x,y,z)} \, dV \approx f\left( \frac{1}{2} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{3}{4} \right)$
$+f\left( \frac{3}{4} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{3}{4} \right) \\ \\ \approx\cos{ \frac{1}{8} }+\cos{ \frac{3}{16} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{9}{32} }+\cos{ \frac{27}{64} } \\ \\ \approx0.9922+0.9825+0.9825+0.9607+0.9825+0.9607+0.9607 \\ +0.9123 \\ \\ \approx\bold{7.734}$

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3 years ago

Which data value has the highest frequency? 1 1/6 3 1/6 3/8 5/8

Marat540 [252]

Answer:

3 1/6

Step-by-step explanation:

To find the highest value, we have to evaluate each term individually,

1) 1 1/6 = 7/6 = 1.167

2) 3 1/6 = 19/6 = 3.16

3) 3/8 = 0.375

4) 5/8 = 0.625

Therefore, second data value (3 1/6) is highest.

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3 years ago

Charissa is eating out with friends, and it is her turn to pay the gratuity. The bill for the food is $26.50. If she plans to ti

sweet [91]

The Tip will be $5.30
So the total she’ll pay is $31.80

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4 years ago

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