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3 years ago

Which point is an x-intercept of the quadratic function f(x) = (x + 6) X – 3)?

Mathematics

1 answer:

Anni [7]3 years ago

5 0

Answer:

(-6, 0) and (3, 0)

Step-by-step explanation:

I think you meant f(x) = (x + 6)(x - 3). This graph intersects the x-axis in two places: (-6, 0) and (3, 0). These are the "x-intercepts."

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Write a proportion that you can use to convert 60 inches to centimeters. any answrs?

Nezavi [6.7K]

How many centimeters in a inch?

1/2.54 = 60/x
2.54 * 60 = x
x= 152.40

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3 years ago

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Please take a look at the picture. Please write your answer with an explanation.

Ahat [919]

Step-by-step explanation:

what answer is needed ? the result of the calculation ?

I assume this is the case.

remember that regarding the sequence of operations brackets are first, then exponents, then "dot" operations (× and ÷), and only at the very least come the "dash" operations (+ and -).

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2 years ago

2x+6=2 <br><br><br> I need help with this plss

Natalka [10]

Step-by-step explanation:

Going to assume you need to know that value of x

2x + 6 = 2

isolate the variable by subtracting 6 on both sides

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5 0

3 years ago

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Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$