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rusak2 [61]
3 years ago
8

What are the coordinates of N?

Mathematics
1 answer:
Nataliya [291]3 years ago
5 0

Answer:

(c,b) are the coordinates of N

Step-by-step explanation:

as N is the mid-point of QR

BY USING MID-POINT FORMULA

N(x,y)=(\frac{x1+x2}{2},\frac{y1+y2}{2})

PUTTING THE VALUES OF COORDINATES

N(x,y)=(\frac{0+2c}{2},\frac{2b+0}{2})

N(x,y)=(\frac{2c}{2},\frac{2b}{2})

N(x,y)=(c,b) are the coordinates

O HOPE THIS WILL HELP YOU :)

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0=x^2-4x+3 how many roots does this equation have
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Answer:

No complex roots; 3 real roots

Step-by-step explanation:

If a third order polynomial has any complex roots, then as a rule it has 1 real root and 2 complex roots.  In this particular case, the polynomial has three real roots, as can be determined by graphing the function.  The graph crosses the x-axis in 3 places.

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Let f(x)=−3x. The graph of f(x) ​is transformed into the graph of g(x) by a vertical stretch of 4 units and a translation of 4 u
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So the equation for these types of equations is f(x) = a(x-h)+k with h being a horizontal translation, a being a stretch/compression and k being a vertical translation. So here if you want a stretch of 4 a would be four, g(x)=4(-3x-h)+k. Also, there is a horizontal translation so it would be positive 4 into the equation. Since there is no change in the y-axis there is no vertical translation resulting in g(x) = 4(-3x-4)
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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

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