graph the linear equation. Find three points that solve the equation, then plot on the graph -x -y =0

Mathematics

1 answer:

konstantin123 [22]3 years ago

4 0

$-x-y=0\qquad\text{add y to both sides}\\\\-x=y\to y=-x\\\\\text{Choice any three x values and calculate the y values.}\\\\for\ x=0\to y=-0=0\to(0,\ 0)\\\\for\ x=-2\to y=-(-2)=2\to(-2,\ 2)\\\\for\ x=2\to y=-2\to(2,\ -2)$

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Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

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If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$