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3 years ago

Martha can complete 15 activities a day at summer camp. She can choose between crafts or sports. Plz help me i need it!!!

Mathematics

1 answer:

Pani-rosa [81]3 years ago

8 0

Answer:

15x2=30 combinations

Or x= activities a day

Y=crafts and sports

D=combinations

XxY=D

Step-by-step explanation: variables would be the activities per day and options of what to do. Multiply those to end up with the total number of combinations.

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Experimental data are collected as:

aliina [53]

Answer:

$y = 1.00114x + 1.75243$

Step-by-step explanation:

Given

The x and y values

Required

The regression line equation

Because of the length of the given data, I will run the analysis using online tools, then analyze the result.

From the analysis, we have:

$\sum x = 5050$

$\sum y = 5231.1011$

$\bar x = 50.5$

$\bar y = 52.311$

$SSX = 83325$ --- Sum of squares

$SP = 83419.7626$ --- Sum of products

The regression equation is calculated as:

$y = ax + b$

Where:

$a = \frac{SP}{SSX}$

So, we have:

$a = \frac{83419.76}{83325}$

$a = 1.00114$

$b = \bar y - a * \bar x$

$b = 52.31 - (1.00114*50.5)$

$b = 1.75243$

So:

$y = ax + b$ becomes

$y = 1.00114x + 1.75243$

6 0

3 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the bin is constructed from 48 square feet of sheet metal, so:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, the dimensions of the largest volume of such a bin is:

Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago

What is the interquartile range? The interquartile range is __

xenn [34]

Answer:

Your IQR or interquartile range is 2.

Step-by-step explanation:

Median: 3

lower quartile: 2

upper quartile: 4

Interquartile range: upper quartile - lower quartile = answer

Interquartile range: 4 - 2 = 2

~hope this helps~

I would highly appreciate it if you give me the brainliest~ :)

4 0

3 years ago

Is 7.64 rational or irrational

Svet_ta [14]

i think its irrational

Step-by-step explanation:

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3 years ago

Cindy made a scale drawing of a game room. The pool table, which is 8 feet long in real life,

krok68 [10]

Answer:

1 inch = 2 feet

Step-by-step explanation:

5 0

3 years ago

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