Then y = 14.
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The (x, y) values that satisfy both equations are (2, 14).
Answer:
Below.
Step-by-step explanation:
7P4
= 7! / (7-4)!
= 7*6*5*4*3*2*1 / ( 3*2*1)
= 7*6*5*4
= 840.
12C5
= 12! / (12-5)! 5!
= 12*11*10*9*8*7*6*5*4*3*2*1 / ( 7*6*5*4*3*2*1 * 5*4*3*2*1)
= 12*11*10*9*8 / 5*4*3*2*1
= 792.
Answer:

Step-by-step explanation:
First you take 3x times 2x since its the first of both equations, which will give you 6x squared.
Then take the outer ones of both problems which is 3x times 3 which is 9x.
Then the inner, -2 times 2x which is -4x
Then the last of both individual problems which is -2 times -3 which is positive 6.
(5ab-7a-9) - (8ab-2)
5ab - 7a - 9 - 8ab + 2
-3ab -7a -7
Answer:
14 days
Step-by-step explanation:
The half life of a substance is the time required until the object has only half of the inicial mass.
So, to find the inicial mass of the object, we use t = 0 in the equation A(t):
A(0) = 600*e^0 = 600
Half of this mass is 300, so we can use A(t) = 300 and then find the time:
300 = 600e^-0.05t
e^-0.05t = 0.5
ln(e^-0.05t) = ln(0.5)
-0.05t = -0.6931
t = 13.862 days
Rounding to nearest day, we have that t = 14 days