Answer:
Step-by-step explanation:
Volume of the shipping container = Lengt * Breadth * Height
Given
Length = 4x² + 3x
Breadth = x² – 8
Height = 6x +15
Volume of the container = ( 4x² + 3x)( x² - 8)(6x+15)
( 4x² + 3x)( x² - 8) = 4x⁴-32x²+3x³-24x
( 4x² + 3x)( x² - 8) = 4x⁴+3x³-32x²-24x
(4x⁴+3x³-32x²-24x)(6x+15) = 24x⁵+60x⁴+18x⁴+45x³-192x³-480x²-144x²-360x
Collect like terms
( 4x² + 3x)( x² - 8)(6x+15) = 24x⁵+78x⁴-147x³-624x²-360x
Hence the standard form polynomial representing the volume of this shipping container is expressed as V = 24x⁵+78x⁴-147x³-624x²-360x
There are four quantum numbers: n, l, ml and ms. When the orbital is 4d, the 4 is corresponding to n. Thus, n=4. Then, the d corresponds to l = 2. Now, to find the value for ml, take the values of -l to +l. Therefore,
<em>ml = -2, -1, 0, 1, 2</em>
<em>Then,ms could only be either +1 or -1.</em>
Answer:
5/6
Step-by-step explanation:
The numbers on a six-sided die are as shown:
1, 2, 3, 4, 5, 6
The even numbers are:
2, 4, 6
The numbers greater than 3 are:
3, 4, 5, 6
Both lists together are:
2, 3, 4, 5, 6
Because 5 out of 6 numbers satisfy these conditions, the probability of satisfying these conditions is 5/6.
Answer: 88 inches
Step-by-step explanation:
We know that the formula to find the circumference of circle is given by :-
, where r is the radius of the circle.
Given : Diameter of circle = 28 inches
Also, diameter is twice of radius.
i.e. 2r=28
Therefore, the circumference of circle will be :-
Hence, the circumference of circle is 88 inches.
Answer:
a) v = 12.21m/s
a = 4.07 m/s²
b)v = 11.24m/s
a = 3.75 m/s²
Step-by-step explanation:
a) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 100
s₀ = x
v = v
t = 9.69 - 3 = 6.69s
s = s₀ + vt
100 = x + v*6.69
100 = x + 6.69v
As x = 3v/2
100 = 3v/2 + 6.69v
100 = 1.5v + 6.69v
100 = 8.19v
v = 12.21m/s
a = v/3 = 4.07 m/s²
b) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 200
s₀ = x
v = v
t = 19.30 - 3 = 16.30s
s = s₀ + vt
200 = x + v*16.3
100 = x + 16.3v
As x = 3v/2
200 = 3v/2 + 16.3v
200 = 1.5v + 16.3v
200 = 17.8v
v = 11.24m/s
a = v/3 = 3.75 m/s²
