Answer:
Cash flow year 0 (110,000)
or in other way to express it: a cashoutflow for $110,000
Explanation:
Initial net cahs outflow
this will be the acquisition of the machine cost plus the increase in the working capital for the company
machine cost: all cost necessary for acquire the machien and get it operational
supplier list price 85,000
installation cost <u> 15,000</u>
total cost 100,000
Increase in Working Capital Cost 10,000
As these are cost they are negative so we have a cashouflow
Total cashflow (110,000)
Answer:
We will get $7680(thousands)
Explanation:
Answer
If we read the given data values in the passage, it is clear that the mean annual number of smart little cars in china is 7500 and the variance is equal to 6400
The variance is given for the number of cars, but not for the profit.
So, we need to convert the numerical value(number of cars) to money value(profit)
it is given that net revenue per car is $1.2 (thousands)
So, multiplying the net revenue by number of cars
we get, variance in profit = 6400*1.2 = $7680 (thousands)
Answer:
Apple Photography, Inc.
Based on this information, the balance in the cash account at the end of January would be:_____.
b) $12,115.
Explanation:
a) Cash Account
Common Stock $13,600
Insurance (2,200)
Service Revenue 5,800)
Rent (1,600)
Office equipment (3,200)
Utilities (285)
Balance $12,115
b) Apple Photography, Inc had a balance in the cash account at the end of January of $12,115 which was the difference between the cash inflows and cash outflows during the month. The inflows represented cash received by Apple Photography from the owners and customers and the cash paid for running the business.
Answer:
a) $3
b) $2
c) 1449
Explanation:
Given:
The cost for a carton of milk = $3
Selling price for a carton of milk = $5
Salvage value = $0 [since When the milk expires, it is thrown out ]3
Mean of historical monthly demand = 1,500
Standard deviation = 200
Now,
a) cost of overstocking = Cost for a carton of milk - Salvage value
= $3 - $0
= $3
cost of under-stocking = Selling price - cost for a carton of milk
= $5 - $3
= $2
b) critical ratio = 
or
critical ratio = 
or
critical ratio = 0.4
c) optimal quantity of milk cartons = Mean + ( z × standard deviation )
here, z is the z-score for the critical ration of 0.4
we know
z-score(0.4) = -0.253
thus,
optimal quantity of milk cartons = 1,500 + ( -0.253 × 200 )
= 1500 - 50.6
= 1449.4 ≈ 1449 units
