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Ulleksa [173]
4 years ago
8

1 over 7 of 2 over 5 is equal to​

Mathematics
1 answer:
natka813 [3]4 years ago
6 0

Answer:

2/35

Step-by-step explanation:

1 over 7 is 1/7, of means times, and 2 over 5 is 2/5, so 1/7*2/5

Hope that this helps!

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Write a recursive rule for the sequence 4,10,16,22
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Answer:

a_{n+1} = a_{n} + 6

Step-by-step explanation:

The terms have a common difference d between consecutive terms, that is

10 - 4 = 16 - 10 = 22 - 16 = 6

To obtain the next term add 6 to the previous term ( recursive rule ), thus

a_{n+1} = a_{n} + 6 with a₁ = 4

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3 years ago
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Answer:

Question 21: -6-(-3)

Question 22: -7+12

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If A=(0,0) and B=(8,2), what is the length of AB
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Answer:

\boxed{\sf Distance_{AB}= 8.24 \ units }

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , <u>A(</u><u>0</u><u>,</u><u>0</u><u>)</u><u> </u>and <u>B(</u><u>8</u><u>,</u><u>2</u><u>)</u> . The distance between the two points can be found out using the<u> </u><u>Distance</u><u> Formula</u><u> </u>, which is ,

<em>Distance Formula:- </em>

\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}

Therefore on substituting the respective values ,we can find the Distance as ,

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<u>Simpl</u><u>i</u><u>fy </u><u>the </u><u>brackets</u><u> </u><u>,</u>

\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}

Square the numbers inside the squareroot ,

\sf\longrightarrow Distance =\sqrt{ 64 + 4}

Add the numbers inside the squareroot ,

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Find the value of squareroot,

\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}

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Answer:

A cube has 6 equal faces, 8 vertices, and 12 edges.

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My answer is self-explanatory.

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