Answer:
sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21
Step-by-step explanation:
During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.
The two numbers are l-16l and l16l. the one that is greater than 12 is l16l
The answer is:
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Explanation:
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Using a scientific calculator;
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Find: "Ten times the quotient of 104,104,104 and 88" ;
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That is; find: 10 * [ (104,104,104) / 88 ] ;
or; write as: 10 * [ 1,183,001.1818181818181818 ] ;
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= 11,830,011.818181818181818...
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