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elena-s [515]
3 years ago
7

GIVEN BRAINLIEST, 5 STARS, + THANKS

Mathematics
1 answer:
Olin [163]3 years ago
6 0

Answer:

<u>Option B. Side YZ is the same length as side Y'X'.</u>

Step-by-step explanation:

At first the image is for the given question

The true graph is the attached figure.

As shown at the attached figure.

XYZ is reflected across the y-axis and then translated down 6 units to form X'Y'Z'.

So, X' is the image of point X

     Y' is the image of point Y

     Z' is the image of point Z

And ΔXYZ ≅ ΔX'YΔ'Z'

And the corresponding length are congruent.

We will check the options:

A. X has the same measure as X'. ⇒ True

B. Side YZ is the same length as side Y'X'. ⇒ Wrong

Because YZ will be translated to Y'Z'

C. Z has the same measure as Z'. ⇒ True

D. Side XZ is the same length as side X'Z'. ⇒ True

<u>So, The answer is option B. Side YZ is the same length as side Y'X'.</u>

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x-width\\2x-length\\\\2x+2\cdot2x=72\\2x+4x=72\\6x=72\ \ \ \ |:6\\x=12\\\\2x=2\cdot12=24\\\\Area=24\cdot12=288\ in^2
3 0
3 years ago
Read 2 more answers
Broderick had $420 in his checking account. He made 6 deposits of $35.50 each. He needs to write 4 checks for $310.75 each.How m
kvasek [131]
So, first you would need to multiply 6 by $35.50, then take that number and add it to the $420 to get $633.00. Then you need to multiply $310.75 by 4. After take that $1243.00 and subtract $633.00 from it to get $610.00. So, the answer is: Broderick would need to add at least $610 to his account to cover his checks.
3 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
7 times as much as sum of 1/3 and 4/5
Salsk061 [2.6K]
So the formula is
7*(1/3+1/5) = x

First find the common denominator of the fractions.  In this case the common denominator of 3 and 5 is 15 so we must convert them to 15ths.  To do that we divide 15 by the denominator and take that answer and multiply the numerator by it.

So for 1/3 we take 15/3(denominator) = 5 and multiply the numerator (1) by it

5 * 1 = 5 so 1/3 converts to 5/15

Do the same for 1/5 we take 15/5 = 3 and multiply the numerator (4) by it

3*4 = 12 so 4/5 converts to 12/15

Now we add 5/15 and 12/15 = 17/15 so we have our formula now to

7*17/15

We make seven a fraction 7/1 and multiply across 7*17 = 119 and 15 * 1 = 15

We have 119/15 which when we divide and get 7 14/15 as your answer
8 0
3 years ago
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Help me please due in 20 minutes
Kamila [148]

Answer:

y=4

Step-by-step explanation:

4 0
2 years ago
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