Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>


Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Answer:
The answer to your question is $9.5
Step-by-step explanation:
Data
Large pizza = L
Medium pizza = m
Write equation for both situations
Situation 1 5L + 2m = 81.5
Situation 2 4L + 3m = 78.5
Solve the system of equation by elimination
Multiply situation 1 by -3 and situation 2 by 2
-15L - 6m = -244.5
8L + 6m = 157
-7L = -87.5
Solve for L L = -87.5/-7
L = $12.5
Substitute L in Situation 1 to find m
5(12.5) + 2m = 81.5
62.5 + 2m = 81.5
2m = 81.5 - 62.5
2m = 19
m = 19/2
m = $ 9.5
The prize of a medium pizza is $9.5
Answer:
-1.8
Step-by-step explanation:
m= y2 - y2over x2 - x1
m= -1 - 8 over 1 - 6 = -1.8
m= -1.8
Answer:
Step-by-step explanation:
1680 mile road trip....they completed 3/8 of it...
so we need to figure 3/8 of 1680
" of " in math language means multiply
3/8 * 1680 = 5040/8 = 630 miles <===
Answer:

Step-by-step explanation:
Given: 76,45,64,80,92
Required: Determine the standard deviation
We start by calculating the mean

Where x-> 76,45,64,80,92 and n = 5



Subtract Mean (71.4) from each of the given data

Determine the absolute value of the above result

Square Individual Result

Calculate the mean of the above result to give the variance


Hence, Variance = 255.298
Standard Deviation is calculated by 


