Ocel’s 10x10=100
Bill’s (10 - y) (10 - y)
I don’t know which answer your teacher wants
100 - [(10-y)(10-y)]
100 - (100 -20y + y^2}
20y - y^2
Two sides are 34 and 14.
The third side can't be longer than (34 + 14) = 48, because the 34 and the 14
together could not reach from one end of it to the other.
The third side also can't be shorter than 20, because the 20 and the 14 together
could not reach from one end of the 34 to the other.
So 18 doesn't work. (18 + 14) = 32 ... they couldn't cover the 34 .
Your answer would be option 2. Use the slope formula to see if any sides are perpendicular. This is because a right triangle must have 2 perpendicular sides that form a 90° angle for it to be a right triangle, so finding these would prove it.
I hope this helps!
Dang if not digit is used more than once then i go with 720 :)
F. 24, this is because if you split the bigger square in half you’ll get 6 and perimeter is the addition of all sides. So 6+6+6+6=24
