Given:
Triangle LJK.
LJ = 89 in, LK = 28 in and m∠L = 42°
To find:
The length of missing side JK.
Solution:
LJ = k = 89
LK = j = 28
JK = l = ?
Using law of cosine:
Substitute the given values.
Taking square root on both sides.
The length of the missing side is 70.7 in.
Answer:
18360
Step-by-step explanation:
A = P (1 + r/n)^(nt) where A is the amount in the account, P is the principle, r is the interest rate , n is the times compounded per year, t is the number of years
A = 17000 (1 + .08/1)^(1*1)
A = 17000( 1.08)^1
A = 18360
Answer:
Step-by-step explanation:
There are choices when it comes to color (3). Then there is the choice between a boy dog or a girl dog (2). Multiply the number of colors by the number of genders. (6)
When choosing a dog from random, you can either choose:
Brown/M
Brown/F
Black/M
Black/F
Yellow/M
Yellow/F
(This list is called the Sample Space, a list of all possible outcomes)
Because the text says that all types of dogs are found in even numbers, it would not matter if there was 6, 12, 18, ... amount of dogs.
When looking at this sample space, you can see that the chance of choosing a Yellow/F dog, is 1 in 6.
General Idea:
Domain of a function means the values of x which will give a DEFINED output for the function.
Applying the concept:
Given that the x represent the time in seconds, f(x) represent the height of food packet.
Time cannot be a negative value, so
The height of the food packet cannot be a negative value, so
We need to replace 
for f(x) in the above inequality to find the domain.
![-15x^2+6000\geq 0 \; \; [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0](https://tex.z-dn.net/?f=%20-15x%5E2%2B6000%5Cgeq%200%20%5C%3B%20%5C%3B%20%20%5BDivide%20%5C%3B%20by%5C%3B%20-15%5C%3B%20on%5C%3B%20both%5C%3B%20sides%5D%5C%5C%20%5C%5C%20%5Cfrac%7B-15x%5E2%7D%7B-15%7D%20%2B%5Cfrac%7B6000%7D%7B-15%7D%20%5Cleq%20%5Cfrac%7B0%7D%7B-15%7D%20%5C%5C%20%5C%5C%20x%5E2-400%5Cleq%200%5C%3B%5BFactoring%5C%3Bon%5C%3Bleft%5C%3Bside%5D%5C%5C%20%5C%5C%20%28x%2B200%29%28x-200%29%5Cleq%200%20)
The possible solutions of the above inequality are given by the intervals ![(-\infty , -2], [-2,2], [2,\infty )](https://tex.z-dn.net/?f=%20%28-%5Cinfty%20%2C%20-2%5D%2C%20%5B-2%2C2%5D%2C%20%5B2%2C%5Cinfty%20%29%20)
. We need to pick test point from each possible solution interval and check whether that test point make the inequality 
true. Only the test point from the solution interval [-200, 200] make the inequality true.
The values of x which will make the above inequality TRUE is 
But we already know x should be positive, because time cannot be negative.
Conclusion:
Domain of the given function is 
Answer:
False
Step-by-step explanation:
Because the gcf of 10 and 18 is 2
