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polet [3.4K]
3 years ago
8

Find the product. Simplify your answer. a/a^2-16 × a+4/a^2​

Mathematics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

\frac{1}{a(a-4)}

Step-by-step explanation:

Factor the denominator of the first fraction

a² - 16 ← is a difference of squares and factors as

a² - 16 = (a - 4)(a + 4), thus fraction becomes

\frac{a}{(a-4)(a+4)} × \frac{a+4}{a^2}

Cancel the factor (a + 4) on numerator/denominator and the a and a², leaving

\frac{1}{a(a-4)}

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