<u>Answer:</u>
(4.75, 4)
<u>Step-by-step explanation:</u>
We are to find the coordinates of the point that partitions the directed line segment AB in 1:3 ration.
For this, we will use the following formula:
,
where is the ratio of the first segment to the whole line segment so in this case, it will .
So substituting the given values in the above formula to find the coordinates:
Therefore, the coordinates of the point that partitions the directed line segment AB in a 1:3 ratio are (4.75, 4).
We know that
speed=distance/time
1) <span>Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr
time=2 1/6 hrs----> 13/6 hrs
speed=6 km/h
distance=speed*time----> 6*(13/6)---> 13 km
2)</span><span>for another 2 hours and 5 minutes with a constant speed of 12 km/hr
time=2hrs+5 minutes----> 2+(5/60)--> 125/60 hrs
speed=12 km/hrs
distance=speed*time----> 12*(125/60)---> 25 km
3) find the </span><span>average speed for the total trip
total distance=13 km+25 km----> 38 km
total time=(13/6)+(125/60)----> (10*13+125)/60----> 4.25 hours
speed=38/4.25----> 8.94 km/hrs
the answer is
8.94 km/hrs</span>
Answer:
Explanation:
Given:
The equation describing the forest wood biomass per hectare as a function of plantation age t is:
y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4
The equation that describes the annual growth in wood biomass is:
y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3
To find:
a) The year the annual growth achieved its highest possible value
b) when does y ′ (t) achieve its highest value?
a)
To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value
SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t
The year the annual growth achieved its highest possible value to the nearest whole number will be
year 4
b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.
Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4
Answer:
about 520,000
Step-by-step explanation:
Following directions, we evaluate the equation by putting the value where the variable is and doing the arithmetic.
__
The value of x will be the number of days between May 26 and May 12. That value is ...
x = 26 -12 = 14
Then the number of mosquitos is estimated to be ...
y = 230,000(1.06^14) ≈ 520,008
About 520,000 mosquitos will inhabit the city on May 26.
_____
<em>Additional comment</em>
Typically, an "estimate" is one or two significant figures. So, 520,000 is a reasonable estimate. 520,008 has more precsision than can be justified.
Okay we’re gonna do the order of PEMDAS. Here is my work! I hope you have a great day or night or whate it is for you.