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nata0808 [166]
3 years ago
8

What is the distance between the point (-7,3) and (4, -5) on a coordinate plane?

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0
To find this, use the distance formula. D= square root over... (x2-x1)^2+ (y2-y1)^2. Now plug in your coordinates.
D= square root... (4- -7)^2+ (-5-3)^2. Simplify. 4- -7=11 (two neg= positive) -5 -3= -8. So,
D= square root... 11^2+ -8^2. Simplify. 11^2= 121. And -8^2=64. Now just take the square root after adding. 121+64= 185. And the square root of 185 isn’t a whole number, so your final answer is D= (square root over) 185. Hope this helps
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Andrea does not understand why if x is a solution to the equation 3-x=4 then x is also a solution to the equation 12=9-3x. Write
Strike441 [17]

Answer:

Both equations are same

Step-by-step explanation:

The reason why this is true is not far fetched

looking at the first equation, we have;

3-x = 4

we can also factorize the second equation to look this way

By this, we shall be having

3(4) = 3(3-x)

By the time we take out the 3 from both sides, we will have the initial equation

So what we are saying is that both equations are the same

6 0
2 years ago
Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
1 year ago
Find the prime factorization of 837.<br> ?
seraphim [82]

Answer:

The Prime Factorization is:

3 x 3 x 3 x 31

In Exponential Form:

33 x 311

Format:

3, 3, 3, 31

Step-by-step explanation:

5 0
3 years ago
Darla and Mary shared a cash prize in the radio 4:5. Together they won a total of $54. Make a tape diagram to determine how much
babunello [35]
She won $30. Please give Brainliest!
6 0
3 years ago
How many centimeters are in 1 mile
kvasek [131]

Answer:

1 mile = 160934 cm

Step-by-step explanation:

1 mile = 1609.34 m

1 m = 100 cm

1 mile = 1609.34 * 100 = 160934 cm

3 0
3 years ago
Read 2 more answers
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