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nata0808 [166]
3 years ago
8

What is the distance between the point (-7,3) and (4, -5) on a coordinate plane?

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0
To find this, use the distance formula. D= square root over... (x2-x1)^2+ (y2-y1)^2. Now plug in your coordinates.
D= square root... (4- -7)^2+ (-5-3)^2. Simplify. 4- -7=11 (two neg= positive) -5 -3= -8. So,
D= square root... 11^2+ -8^2. Simplify. 11^2= 121. And -8^2=64. Now just take the square root after adding. 121+64= 185. And the square root of 185 isn’t a whole number, so your final answer is D= (square root over) 185. Hope this helps
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When no more than 110 units are produced, the cost of producing y units is given by C(x).
Maslowich

Producing 73.8 units gives the lowest possible average cost.

The average cost (AC) is the ratio of the total cost to the number of units produced. It is given by:

AC = C(x) / x

AC = (0.2x³ – 24x² + 1514x +30064) / x

AC = 0.2x² - 24x + 1514 + 30064/x

The lowest possible average cost is at AC' = 0. Hence differentiating the average cost, gives:

AC' = 0.4x - 24 - 30064/x²

0.4x - 24 - 30064/x² = 0

0.4x³ - 24x² - 30064 = 0

Solving the cubic polynomial gives:

x = 73.8 units

Therefore the lowest possible average cost is when 73.8 units are produced.

Find out more at: brainly.com/question/20346871

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