What additional information can be used to prove ΔDSB ≅ ΔTSR by SAS?
2 answers:
Please find the attached file for a proper understanding of the question given here. The diagram in the file attached is the complete accompanying diagram of the question.
As per that diagram, (which is given)
and we know that (vertically opposite angles).
Thus, the only way ΔDSB ≅ ΔTSR by SAS is when as indicated in the diagram.
Thus, is the correct answer.
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Answer:
0.25 or 25%
Step-by-step explanation:
There are 4 possible outcomes for each die, which gives us 16 possible combinations (4 x 4). In order for the sum to exceed 5, the possible outcomes are:
Red = 3, and Green = 3
Red = 3, and Green = 4
Red = 4, and Green = 3
Red = 4, and Green = 4
Therefore, the probability of winning on a single play is:
The probability is 0.25 or 25%.
Answer:
if repetition is allowed,
if repetition is not allowed.
Step-by-step explanation:
For the first case, we have a choice of 26 letters <em>each step of the way. </em>For each of the 26 letters we can pick for the first slot, we can pick 26 for the second, and for each of <em>those</em> 26, we can pick between 26 again for our third slot, and well, you get the idea. Each step, we're multiplying the number of possible passwords by 26, so for a four-letter password, that comes out to 26 × 26 × 26 × 26 = possible passwords.
If repetition is <em>not </em>allowed, we're slowly going to deplete our supply of letters. We still get 26 to choose from for the first letter, but once we've picked it, we only have 25 for the second. Once we pick the second, we only have 24 for the third, and so on for the fourth. This gives us instead a pretty generous choice of 26 × 25 × 24 × 23 passwords.