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Pepsi [2]
3 years ago
7

Irene makes a second batch of 3 and 1/4 cups of pancake batter. She wants to know how much more batter she made in the first bat

ch. She estimates that the difference between the sizes of the two batches 4 and 2/3 - 3 and 1/4 is 2 and 1/12. Explain why this estimate is not reasonable.
Mathematics
2 answers:
Zarrin [17]3 years ago
8 0
4 2/3 is equal to 4 8/12. 3 and 1/4 is equal to 3 3/12. 4 8/12- 3 3/12 = 1 5/12. 1 1/2 would be a better estimate.
Vlad1618 [11]3 years ago
4 0

The estimate is not reasonable because

4 2/3 is equivalent to 4 8 /12 ,

and 3 1/4 is equivalent to 3 3/12,

4 \frac{8}{12}  -  3  \frac{3}{12}   = 1 \ \frac{5}{12}

  1. so , 2 1/12 wasn't a good estimate
  2. and , 2 1/12 isn't a great estimate because 6/12 is equivalent to 1/2 and 1 /12 is way less than 6/12
  3. hope it helps plz mark as brainliest

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A phone sells for $250. It is now on sale for 1··5off the original price. April has a coupon for an extra 10% off the sale price
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It's on a sale for 1 fifth of the original price?

4 0
3 years ago
2. There are 42 persons in a mathematics class, and everyone of them drinks either coffee or grape milk at
Basile [38]

Answer:

1.  8

2.  24

Step-by-step explanation:

The number of persons that drink grape milk only :

18 - 10 = 8

The number of persons that drink coffee :

42 - 8 = 34

The number of persons that drink coffee only :

34 - 10 = 24

5 0
2 years ago
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
3 years ago
Mary planted 5/8 rows of beans and 8/9 rows of carrots in a garden. In total,how many rows of vegetables did Mary plant?
kupik [55]
Rows of beans = 5/8
Rows of carrots = 8/9

Total number of rows = 5/8 + 8/9
= (45 + 64)/72
= 109/72

Hope This Helps You!
4 0
3 years ago
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