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3 years ago

The equation of line L, is y = 5x + 1

Mathematics

1 answer:

Lynna [10]3 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

Parallel lines have equal slopes.

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x + 1 ← is in slope- intercept form

with slope m = 5

Rearrange 2y - 10x + 3 = 0 into this form

Add 10x to both sides

2y = 10x ( subtract 3 from both sides )

2y = 10x - 3 ( divide all terms by 2 )

y = 5x - $\frac{3}{2}$ ← in slope- intercept form

with slope m = 5

Since both lines have a slope of 5 then they are parallel.

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Please help!! I will venmo

QveST [7]

Answer:

30 cm^2

Step-by-step explanation:

the triangle is 36

the rectangle is 6

36-6=30

5 0

2 years ago

)Consider the following pair of equations: y = −2x + 8 y = x − 1 Explain how you will solve the pair of equations by substitutio

Ira Lisetskai [31]

Hi there,

Take y from first equation and use it / substitute it into the second equation:

-2x + 8 = x - 1, so 3x = 9, therefore x = 3.

Then y = x - 1 = 3 - 1 => y = 2.

Solution is (3,2).

A quick check: 2 = -2*3 + 8, true, and 3 = 2 - 1, also true.

Green eyes.

5 0

2 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

2 years ago

What is the mode of the data set? (Please help)

Snowcat [4.5K]

Answer:

the number that occures the most is the answer

Step-by-step explanation:

7 0

2 years ago

Evaluate the function g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.

Roman55 [17]

Evaluate the function

g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.

This is tedious math work but necessary to sharpen your skills.

Let x = -2

g(-2) = 2(-2)^2 + 3(-2) – 5

g(-2) = 2(4) - 6 - 5

g(-2) = 8 - 11

g(-2) = -3

Now let x = 0 and repeat the process.

g(0) = 2(0)^2 + 3(0) - 5

g(0) = 0 + 0 - 5

g(0) = -5

Lastly, let x = 3.

g(3) = 2(3)^2 + 3(3) - 5

g(3) = 2(9) + 9 - 5

g(3) = 18 + 9 - 5

g(3) = 27 - 5

g(3) = 22

Did you follow through each step?

4 0

2 years ago