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Novay_Z [31]
3 years ago
7

Volume of cone round to the nearest 10th

Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer: 63

Maybe?

If it’s wrong sorry :)

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67. The line contains the point (4,0) and is parallel<br> to the line defined by 3x = 2y.
olganol [36]

Answer:

y=\frac{3}{2} x-6

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form:
  • y=mx+b where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
  • Parallel lines will always have the same slope but different y-intercepts.

<u>1) Determine the slope of the parallel line</u>

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

3x = 2y

Switch the sides

2y=3x

Divide both sides by 2 to isolate y

\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x

Now that this equation is in slope-intercept form, we can easily identify that \frac{3}{2} is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope \frac{3}{2} . Plug this into y=mx+b:

y=\frac{3}{2} x+b

<u>2) Determine the y-intercept</u>

y=\frac{3}{2} x+b

Plug in the given point, (4,0)

0=\frac{3}{2} (4)+b\\0=6+b

Subtract both sides by 6

0-6=6+b-6\\-6=b

Therefore, -6 is the y-intercept of the line. Plug this into y=\frac{3}{2} x+b as b:

y=\frac{3}{2} x-6

I hope this helps!

7 0
3 years ago
Evaluate arccsc square root of 2
leonid [27]
Sin⁻¹ √2 = 1/√2 = 1(√2) / (√2)(√2) = √2/2
8 0
3 years ago
A kangaroo can jump 6 times the length of its body. For a kangaroo that is 5 feet long, how many feet can it jump? *
Sindrei [870]

Answer:

30feet

Step-by-step explanation:

5 x 6 =30

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tggvbvvnvcvbb

6 0
3 years ago
Read 2 more answers
A ball is dropped from a height of 100 cm. The rebound heights to the nearest centimeter are 60, 36, 22, .... What is the total
Nataly_w [17]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
You paid $44 to a loan company for the use of $1,153 for 119 days, what annual rate of interest did they charge? (Assume a 360-d
Zigmanuir [339]

Answer:

Ans. A) The annual rate that the company charged was 11.996%; B) if they charged you 11.186% annual rate, you would have to pay $41.14

Step-by-step explanation:

Hi, first we have to find out what is the effective 119 days rate and then turn it into an annual rate. This is as follows.

r(Effective119Days)=\frac{44}{1,153} x100=0.038161

So the charged rate was 3.816% effective, 119 days, now let´s make it an annual rate.

r(annual)=(1+0.038161)^{\frac{360}{119} } -1=0.119965

This means that the equivalent rate to 3.816% effective 119 days ys 11.996% effective annually (or just annual).

Now, if they were to charge you 11.186% annual, you would have to make this rate effective 119 days, and then, multiply it by the principal ($1,153). Let´s change the rate first.

r(Effective119Days)=(1+0.11186)^{\frac{119}{360} -1}=0.03568

And the money that you will have to pay in interest is $1,153*0.03568=$41.14

Best of luck

7 0
3 years ago
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