Solve for y in 3x+7=y
y=7−3x
Substitute y=7−3x
y=7−3x into 8x−3y=30
8x−3y=30.
17x−21=30
Solve for x
x in 17x−21=30
17x−21=30.
X=3
Substitute x=3 into y=7−3x
y=-2
Therefore,
x=3
y=−2
Answer:
The rocket hits the ground at a time of 11.59 seconds.
Step-by-step explanation:
The height of the rocket, after x seconds, is given by the following equation:
It hits the ground when 
, so we have to find x for which , which is a quadratic equation.
Finding the roots of a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
In this question:
So
Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.
Answer:
∠ WUV = 36°
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ VWX is an exterior angle of the triangle, thus
8x - 18 = 2x + 8 + 3x + 16
8x - 18 = 5x + 24 ( subtract 5x from both sides )
3x - 18 = 24 ( add 18 to both sides )
3x = 42 ( divide both sides by 3 )
x = 14
Thus
∠ WUV = 2x + 8 = 2(14) + 8 = 28 + 8 = 36°
Take 3÷2.6=1.153846repeating. So around $1.15. To check you can take the decimal point times by 2.6 and it will give you three.
Answer:
D
Step-by-step explanation:
