Answer:
the solution is (-2,3)
Step-by-step explanation:
a
Planes X and Y are perpendicular. Points A, E, F, and G are points only in plane X. Points R and S are points in both planes X a
nd Y. Lines EA and FG are parallel.
Based on this information, which lines could be perpendicular to RS? Check all that apply.
EA,ER,EF,FG,FS
Based on this information, which lines could be perpendicular to RS? Check all that apply.
EA,ER,EF,FG,FS
2 answers:
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The correct answer would be 
In order to solve for this you must first get the equation equal to 0.
<span>x^2=-5x-3 ----> add 5x to both sides.
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
And those would be your two answers.
In order to solve for this you must first get the equation equal to 0.
<span>x^2=-5x-3 ----> add 5x to both sides.
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
And those would be your two answers.