1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry [639]
3 years ago
9

Sydney borrowed $5500 from the bank to pay for her first semester of college. The loan has a simple interest rate of 6% for the

length of the 5-year loan. How much interest will Sydney have paid?
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

$330

Step-by-step explanation:

You might be interested in
A pole that is 2.8 m tall casts a shadow that is 1.67 m long. At the same time, a nearby building casts a shadow that is 50.75 m
Veseljchak [2.6K]

Answer:

Explanation:

3.2

1.14

=

x

44.75

Cross Mutliply:  

44.75

⋅

3.2

=

1.14

x

Divide:  

143.2

1.14

=

x

You get 125.614 rounded to the nearest meter is 126

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
James is studying different kinds of weather.
ivann1987 [24]

Answer:

i got b and h{i hope this helps}

Step-by-step explanation:

6 0
3 years ago
Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v
blagie [28]
U = ( -8 , -8)
v = (-1 , 2 )
<span>the magnitude of vector projection of u onto v =
</span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll
</span>
<span>ll v ll = √(-1² + 2²) = √5
</span>
u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8 
∴ <span>(u . v )/ ll v ll = -8/√5</span>
∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll]
</span>
<span>                          = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 )
</span>
The other orthogonal component = u - ( 8/5 , -16/5 )
                                   = (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 )
</span>
So, u <span>as a sum of two orthogonal vectors will be
</span>
u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>










3 0
3 years ago
Read 2 more answers
Find x if 2^x=8^3x-8
Anon25 [30]

Step-by-step explanation:

First we have to same the bases.

As we know 8=2^3.

Replace 8 with 2^3.

Like this .

2^3x=2^3(2x+1).

Now 3x=3(2x+1) distribute 3 by the Barker.

3x=6x+3.

6x+3=3x.

6x-3x=-3.

3x=-3.

X=-1.

5 0
2 years ago
A box has two balls, one white and one red. We select one ball, put it back in the box, and select a second ball (sampling with
AleksAgata [21]

Answer:

P (T) = 1/4

P ( T | F )    = 1/2  = P(F)

The events are not independent.

Step-by-step explanation:

Let F the event of picking the white ball first

P (F)= 1/2   ( picking the white ball first)

Let T be the event of getting the white ball twice,

P (T) = P( getting white ball) * P( getting white ball)

          =( 1/2)*(1/2)

           = 1/4

Here P(T∩F) = P(T) because the probability of getting the white balls is the same as probability of getting the white ball first  both the times.

P ( T | F ) = P (T∩F)/ P(F)

                = (1/4)/ (1/2)

                  = (1/2)

                    = 1/2  = P(F)

For the events to be independent the conditional probability P ( T | F )  must be equal to P(T).

Hence the events are not independent.

4 0
3 years ago
Other questions:
  • What are the coordinates of the pre-image of B'?
    8·2 answers
  • Simplify the following expression.
    14·2 answers
  • 1. what is 10% of 20? 2.What is 5% of 10?
    15·2 answers
  • PLEASE HELP WILL GIVE BRAINLIEST<br> Answer all parts of the question please!
    15·1 answer
  • If a=3 and b=7 find the value of<br>2ab​
    5·1 answer
  • HELP giving brainlest and extra points
    10·1 answer
  • A farm lets you pick 3 pints of raspberries for $12.00.
    6·1 answer
  • PLEASE CLICK ON THIS IMAGE I NEED HELP
    9·2 answers
  • Will give brainlist if correct!
    12·1 answer
  • Helppppppppppppppppppppppppppppppppppppppppppppppppp
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!