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Alex Ar [27]
3 years ago
12

6. There are 3 consecutive positive integers. The product of the smaller two integers is two more than ten times

Mathematics
2 answers:
frutty [35]3 years ago
7 0
The answer is letter B
Elanso [62]3 years ago
7 0
The answer is letter C!! 11x12=132 13x10=130. 132 is 2 more than 130
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(8+2)-5=???????????????????
sasho [114]

Answer:

<h2>5</h2>

Step-by-step explanation:

<h2>8+2 -5</h2><h2>8+2=10 - 5 </h2><h2>10 -5 = 5 </h2>

<h2>(◍•ᴗ•◍)✧*。</h2>

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5 0
3 years ago
Read 2 more answers
In the figure to the right, can you conclude that triangle GHI is congruent to triangle KJI? Justify your reasoning.
inessss [21]

Answer:

No

Step-by-step explanation:

You cannot conclude that ΔGHI is congruent to ΔKJI, because although you can see/interpret that there all the angles are congruent with one another, like with vertical angles (∠GIH and ∠KIJ) and alternate interior angles (∠H and ∠J, ∠G and ∠K), we don't know the side lengths.

All the angles could be congruent, but the sides might be different. For example, ΔGHI might be a bigger triangle than ΔKJI, which could make them similar to one another, but not congruent.

For something to be congruent to another, everything must be exactly the same.

7 0
3 years ago
Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t
Anika [276]

Answer:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c

Step-by-step explanation:

Given

\int\limits {\frac{x}{x^4 + 16}} \, dx

Required

Solve

Let

u = \frac{x^2}{4}

Differentiate

du = 2 * \frac{x^{2-1}}{4}\ dx

du = 2 * \frac{x}{4}\ dx

du = \frac{x}{2}\ dx

Make dx the subject

dx = \frac{2}{x}\ du

The given integral becomes:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du

Recall that: u = \frac{x^2}{4}

Make x^2 the subject

x^2= 4u

Square both sides

x^4= (4u)^2

x^4= 16u^2

Substitute 16u^2 for x^4 in \int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du

Simplify

\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du

In standard integration

\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)

So, the expression becomes:

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)

Recall that: u = \frac{x^2}{4}

\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c

4 0
3 years ago
How many pages can Jorge print in 3/5 of an hour if he can print 24 pages every 15 minutes?
MariettaO [177]

Answer:

57.6 pages

Step-by-step explanation:

First, you need to identify how many minutes are in 3/5 of an hour:

1 hour = 60 minutes

3/5 of an hour = 3/5 of 60 minutes

= 3/5(60)

= 36

So, you need to find out how many pages can be printed in 36 minutes. To figure this out, a ratio can be used:

15 : 24

36 : p

p represents pages in 36 minutes.

Now, you need to solve the ratio by figuring out what you need to multiply 15 by to get 36 and then multiplying that by 24:

15 * 36/15 = 36

36/15 = 2.4

24*2.4

= 57.6 pages

5 0
3 years ago
Which expression is equivalent to the one below?
FromTheMoon [43]
9 divided by 13 = 9/13

None of the answer above
Should be: 9 • 1/13
7 0
3 years ago
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