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ddd [48]
3 years ago
14

What must be added to x - y to obtain y-x?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0
To make x-y reasonable, you must make x the same value as y. It is the same as y-x. But a different variable order. For example x= 6 and y=9, and x - y is unreasonable, to make it reasonable, you must add 3 more to x to make it the way of y - x. So, your answer is just like 9-9 or 10-10 or any other subtraction equation with equal value, you don’t have to know what the variables equal, you just have to take an example and try it, that’s all you need to do to get out of the tricky problems. Hope this helps and have a great night of sleep :))
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Solve the equation:<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%7D%20x%5E%7B2%7D%20%2B%204%20-%201%20%3D%202" id="TexFormula1" t
Georgia [21]

Answer:

D) x = √5

Step-by-step explanation:

\sqrt{x^{2}+4 }-1 = 2

\sqrt{x^{2}+4 } = 3

x^{2}+4 = 3^{2}

x^{2}+4 = 9

x^{2} = 9 -4

+x = \sqrt{5} ,  -x = \sqrt{5}

3 0
2 years ago
What is solution of 8x-2y =1 and -4x+y = 3
Maksim231197 [3]

Answer: it has no solution

Step-by-step explanation:

8x - 2y = 1 ..................... equation 1

-4x + y = 3 ...................... equation 2

solving the system of linear equation by substitution method . From equation 2 , make y the subject of the formula.

y = 3 + 4x .......................... equation 3

substitute equation 3 into equation 1 .

8x - 2(3 + 4x ) = 1

8x - 6 - 8x = 1

8x- 8x - 6 = 1

-6 = 1

this means that the equation has no solution

6 0
3 years ago
Find arc DC please help me
emmasim [6.3K]

Answer:

arc ABC = 196°

arc DC = 360 - 196 - 70 = 94°  (which looks out of proportion, but so does angle D)

Step-by-step explanation:

arc ABC = 2(∠D) = 2(98°) = 196°

3 0
3 years ago
Box and whisker plot how do you find the percentage of students above an 80%
IgorLugansk [536]
What do you mean? Please message me the question and I will gladly help
4 0
3 years ago
A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.
zmey [24]

Answer:

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation  

\bar X=2.2 represent the sample mean

s=0.29 represent the sample standard deviation

n=40 sample size  

\mu_o =2.1 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.1  

Alternative hypothesis:\mu > 2.1  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0
3 years ago
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