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Nina [5.8K]
3 years ago
9

Find the angle that makes them supplementary.

Mathematics
1 answer:
Semmy [17]3 years ago
7 0

Answer:

130,110,40,90,165

Step-by-step explanation:

supplementary angles add up to 180

so 180-50= 130

180-70=110

etc

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What is the standard form of the number shown in this calculator display?
dem82 [27]

Answer:

  38,200,000

Step-by-step explanation:

Put the 3 in the 8th spot to the left of the decimal point and fill in the other digits to the right of it.

  38,200,000

__

The first spot immediately to the left of the decimal point has a place value of 10^0, so the location with a place value of 10^7 is the 8th spot left of the decimal point. You should be able to get the idea from the attached.

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If you put your calculator in the appropriate display mode, it should show you the number in this form.

8 0
3 years ago
How many 3/8 are in 5/4
Sonja [21]

Answer:20

Step-by-step explanation:

7 0
3 years ago
247 is 38 percent of what amount? ❓
prisoha [69]
The question is asking that X times 38% will equal to 247. So we set up the equation:

x *  \frac{38}{100}  = 247

Then, we multiply both sides by \frac{100}{38}

and we get the answer is 650
7 0
3 years ago
Read 2 more answers
Given the function: f(x) = 2x3 - 3/2x, find f(-4).
Sergeu [11.5K]

Answer:

D) -122

Step-by-step explanation:

Given:

f(x) = 2x^3-\frac{3}2x

We need to find f(-4).

Now by substituting the value of x =-4 in above equation we get;

f(-4)= 2\times(-4)^3-\frac{3}{2}\times(-4)\\

By using PEDMAS we will solve for exponential function first we get;

Now we know that (-4)^3=-64

So we get;

f(-4)= 2\times(-64)-\frac{3}{2}\times(-4)\\

Now using PEDMAS we will solve division.

f(-4)= 2\times(-64)-1.5\times(-4)

Now using PEDMAS we solve multiplication.

f(-4)= -128+6

Finally by subtraction we get;

f(-4)= -122

5 0
3 years ago
Consider an unreliable communication channel that can successfully send a message with probability 1/2, or otherwise, the messag
Anon25 [30]

Answer:

6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

Step-by-step explanation:

Consider the provided information.

Let x is the number of times massage received.

It is given that the probability of successfully is 1/2.

Thus p = 1/2 and q = 1/2

We want the number of times do we need to transmit the message over this unreliable channel so that with probability 63/64 the message is received at least once.

According to the binomial distribution:

P(X=x)=\frac{n!}{r!(n-r)!}p^rq^{n-r}

We want message is received at least once. This can be written as:

P(X\geq 1)=1-P(x=0)

The probability of at least once is given as 63/64 we need to find the number of times we need to send the massage.

\frac{63}{64}=1-\frac{n!}{0!(n-0)!}\frac{1}{2}^0\frac{1}{2}^{n-0}

\frac{63}{64}=1-\frac{n!}{n!}\frac{1}{2}^{n}

\frac{63}{64}=1-\frac{1}{2}^{n}

\frac{1}{2}^{n}=1-\frac{63}{64}

\frac{1}{2}^{n}=\frac{1}{64}

By comparing the value number we find that the value of n should be 6.

Hence, 6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

7 0
3 years ago
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