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Ann [662]
3 years ago
8

Is this table proportional or non-proportional X 8,16,24,32 Y 2,4,6,8

Mathematics
1 answer:
Temka [501]3 years ago
6 0
The table is Proportional
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Given that |-5| > 3, which statement is not true
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What are the answer choices
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3 years ago
In an effort to save the environment, Stacey makes a classroom presentation about how many gallons of water a dripping faucet ca
rusak2 [61]
(3,15)(6,30)
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5 0
3 years ago
Solve.
Serggg [28]

Answer:

The solution is (4, 0)

Step-by-step explanation:

Using Linear combination method to solve:

2d + e = 8\\d - e = 4\\

Since "e" have the same coefficient in both equation with opposite operator; we will add.

(2d + d) + (e - e) = (8 + 4)\\3d = 12\\

Divide both side by coefficient of d which is 3

\frac{3d}{3}  = \frac{12}{3} \\d = 4\\

Since d = 4; put 'd' into any of the equation to get 'e'

2d + e = 8\\2(4) + e = 8\\8 + e = 8\\e = 8 - 8\\e = 0\\

Therefore, the solution is (4, 0)

5 0
3 years ago
What is the surface area of the solid...?​
ryzh [129]
580 square units !!
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5 0
2 years ago
Three stamps can be attached to each other in various ways.how many ways might three stamps be attached?
ivanzaharov [21]
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula. 
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C. 
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space. 
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.


8 0
3 years ago
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