Answer:
398.71 ft
Step-by-step explanation:
Length of rebar = 18 inches = 1.5 ft
Elevation = 393.66 ft
Reading of backsight on Benchmark= 7.56 ft
Rod reading = 1.10 ft
<em>First step : determine height of Instrument been used</em>
= elevation + backsight on Benchmark
= 393.66 + 7.56 = 401.22 ft
<em>Elevation of top of rebar </em>
= 401.22 - 1.01 = 400.21 ft
Finally determine the elevation of the top of the pipe
= 400.21 - length of Bar
= 400.21 - 1.5 = 398.71 ft
6x=120-5y -> x=20-5/6*y -> 7(20-5/6*y) + 11y =202 -> 140-35/6*y + 11y = 202 -> 140+31/6*y=202 -> 31/6*y = 62 -> y = 12.
It will be 69• degreessssss bro bor8182)2(/
In order to do this you need a system of equations. One equation is going to be about the numbers of people, the other is going to be about the money: what it costs for each type of person and the total amount of money earned. Money and numbers of people are 2 different things so they have to be in 2 different equations. We know that there were children and adults that went to the park and that the total NUMBER of people is 220. That means that adults plus children equal 220 people total. Or, in equation form, a + c = 220. Now the money part. Each child costs 2.25, so the cost of a child is 2.25c; each adult costs 6.20, so the cost of an adult is 6.20a. The total amount of money earned was 890. That equation is 2.25c + 6.20a = 890. Solve the first equation for a: a = 220 - c. Now sub in that value for a in the money equation, like this: 2.25c + 6.20(220-c) = 890. Solve this for c. 2.25c+1364-6.2c = 890. Combine like terms to get -3.95c = -474. Divide both sides by 3.95 to get that c = 120. There were 120 children out of the 220 people that attended. That means that there were 220-120 adults, or 100 adults. There you go!
Answer:
The question is incomplete or there are details missing.
Step-by-step explanation:
From similar parameters, if by what they mean is that the football field measures 300feet in length, which is the dimension in length, this can also be in terms of metre.
The conversion factor between ft and metre is 1ft = 0.3048m
As such, we can only have variations or the length of the field measured may have ranges of measurement, but as it is the length of the field can not be expressed in terms of miles, the most reasonable vale of n we can get will be the least measurement in metres.
