Which choice is the solution?

The sum of two consecutive odd numbers is 284. Find each number please.

Vlad [161]

We can solve this by finding one of the numbers first
Let the smaller number be y.
Since these 2 numbers are consecutive odd numbers, the larger number should be 2 more than the smaller one (y+2).

Therefore,
y + (y+2) = 284
2y +2 = 284
shift +2 to the other side and turn it into -2
2y = 284 - 2
2y = 282
shift x2 to the other side and turn it into /2
y = 282/2
y = 141

Now we got the smaller number, which is 141, we can also find the larger number by adding 2 to it. 141+2 = 143,
Therefore, your answer is 141 and 143

8 0

3 years ago

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Cindy put equal sized marbles into a bowl. Then, she shook the bowl until 3 marbles fell out. Is this a random sample of the mar

myrzilka [38]

Answer:

Yes

Step-by-step explanation:

I'm assuming this is right

6 0

3 years ago

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In one day Sasha got 1 hour of sleep for every 3 hours she was awake if there are 24 hours in a day how many hours of sleep did

Gre4nikov [31]

Answer:

Hours slept = 6 hours

Hours awake = 18 hours

Step-by-step explanation:

Sasha got 1 hour of sleep for every 3 hours she was awake.

So,

<u>This means:</u>

Slept : Awake = 1 : 3

Total hours in a day = 24 hours

Hours slept = 1x and hours awake = 3x

<u>Hence,</u>

1x + 3x = 24 hours

4x = 24

Divide both sides by 4

x = 24 / 4

x = 6

Hours slept = 1(6) = 6 hours

Hours awake = 3(6) = 18 hours

$\rule[225]{225}{2}$

Hope this helped!

6 0

2 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim (x, y) → (0, 0) x4 − 34y2 x2 + 17y2

HACTEHA [7]

Answer:

Step-by-step explanation:

Given the limit of the function $\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}$ , to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

$= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)$

Step 2: Substitute y = mx int o the function and simplify

$= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\$

$= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\$

<em>Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE</em>

4 0

3 years ago

Question:

Slav-nsk [51]

Answer: well it depends on what you are aiming for I would say 3 or 5 as there is a 15 so maybe it would want you to divide or multiply I am only in 7th grade but I hope this helps

Step-by-step explanation:

15/3=5 15/3=5

7 0

2 years ago