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professor190 [17]
3 years ago
11

I will give u brainliest

Mathematics
2 answers:
Leto [7]3 years ago
5 0

Answer:

52/99

Step-by-step explanation:

idk i looked it up

telo118 [61]3 years ago
4 0

Answer:

52/99.

Step-by-step explanation:

52 divided by 99 equals 0.525252. This can also be written as a fraction, which looks like this: \frac{52}{99}.

<em>I hope this helps! Feel free to give me Brainliest if you feel this helped! :)</em>

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Answer:

12 miles

Step-by-step explanation:

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8 0
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Please help FAST:
Alex_Xolod [135]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
What is A number divided by 82
lara [203]

Answer:

Hey there, Lets solve this step by step.  

A number t divided by 82  

Let the number be represented by y.  

t divided by 82 = t / 8  

Therefore-  

 

In algebraic expressions, "y" is normally used as the dependent variable and "x" is normally used as the independent variable, instead of other variables. So that is why i used the variable y in the equation.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is the approximate area of the circle that fits perfectly inside of the square? Use Pi = 3.14 and round to the nearest tent
Pani-rosa [81]

Answer:

19.625\text{ cm}^2

Step-by-step explanation:

GIVEN: A square with base 5\text{ cm}, a circle that perfectly fits inside square.

TO FIND: Approximate area of circle.

SOLUTION:

Consider the figure attached.

let the radius of circle be x\text{ cm}

radius of circle =\frac{\text{length of base of square}}{2}

                     x=\frac{5}{2}\text{ cm}

                     x=2.5\text{ cm}

Area of circle =\pi(radius)^2

                      =3.14\times(2.5)^2

                      =19.625\text{ cm}^2

Hence the area of circle that perfectly fits inside the square is 19.625\text{ cm}^2

6 0
3 years ago
Read 2 more answers
Solve for x.<br> 4 - 3x<br> 2<br> = 5<br> A) -2 <br> B) -<br> 1<br> 2<br> C) <br> 1<br> 2<br> D) 2
Fudgin [204]

Answer:

This problem was pasted incorrectly

Step-by-step explanation:


4 0
2 years ago
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