All categories

3 years ago

Please help me on the full page

Mathematics

1 answer:

n200080 [17]3 years ago

3 0

Part A.

bh + hr = 25

h( b + r ) = 25

h = 25/ b + r

Part B

hr = 25 - bh

r = (25 - bh)/h

r = 25/h - b

Part A.

xy = r - h

-h = -r + xy

divide both sides by -1

h = r - xy

Part B

xy = r - h

xy + h = r

r = xy + h

4x - 2y = 8

-2y = 8 - 4x

divide through by -2

y = 8/-2- 4x/-2

y = -4 + 2x

therefore Camille solved the equation correctly

You might be interested in

Which is more precise 42.7 cm or 427.0 mm

notsponge [240]

427.0 mm is more precise.
feel free to ask any questions

3 0

3 years ago

Numbers expressed using exponents are called .

N76 [4]

Answer:

numbers expressed using exponents are called powers

4 0

2 years ago

Read 2 more answers

The cross section of a water bin is shaped like a trapezoid. The bases a a trapezoid are 20 feet and 6 feet long. It has a area

nekit [7.7K]

Answer:

the height of the cross section is 3 feet

Step-by-step explanation:

The computation of the height of the cross section is shown below:

Area = 1 ÷ 2 × (a + b) × h

39 = 1 ÷ 2 × (20 + 6) × h

39 = 1 ÷2 × 26 × h

39 = 26 ÷ 2 × h

39 = 13 × h

h = 39 ÷ 13

= 3 feet

hence, the height of the cross section is 3 feet

3 0

2 years ago

A cheetah can run at a speed of 60 miles per hour how far can it run in 0.5 hours

damaskus [11]

30 miles
Because you’re cutting the time in half and the same should apply to the speed

4 0

2 years ago

Helpppp me please!!!

Semenov [28]

To find the value of q, we need to find d(-8). Put another way, we need to find the value of d(x) when x = -8

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(-8) = -\sqrt{\frac{1}{2}(-8)+4}$

$d(-8) = -\sqrt{-4+4}$

$d(-8) = -\sqrt{0}$

$d(-8) = 0$

So this means q = 0. Note that -0 is just 0.

===========================================

The value of r will be a similar, but now we use f(x) this time.

Plug in x = 0

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(0) = \sqrt{\frac{1}{2}*0+4}$

$f(0) = \sqrt{0+4}$

$f(0) = \sqrt{4}$

$f(0) = 2$

Therefore, r = 2.

===========================================

For s, we plug x = 10 into f(x)

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(10) = \sqrt{\frac{1}{2}*10+4}$

$f(10) = \sqrt{5+4}$

$f(10) = \sqrt{9}$

$f(10) = 3$

So s = 3.

===========================================

Finally, plug x = 10 into d(x) to find the value of t

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(10) = -\sqrt{\frac{1}{2}(10)+4}$

$d(10) = -\sqrt{5+4}$

$d(10) = -\sqrt{9}$

$d(10) = -3$

A shortcut you could have taken is to note how d(x) = -f(x), so this means

d(10) = -f(10) = -9 since f(10) = 9 was found in the previous section above.

Whichever method you use, you should find that t = -3.

===========================================

<h3>In summary:</h3><h3>q = 0</h3><h3>r = 2</h3><h3>s = 3</h3><h3>t = -3</h3>

8 0

2 years ago